Javascript 如何从给定的代码中获取JSON对象?

Javascript 如何从给定的代码中获取JSON对象?,javascript,json,Javascript,Json,我正在使用url我的代码是: var url="http://nucleus/api/projectlist?format=json" var json=JSON.parse(this.responseText); 浏览器中JSON格式的数据如下所示 { "1": { "id": "91", "title": "Nucleus Aura", "project_locations": "TVm, Kochi", "proj

我正在使用url我的代码是:

var url="http://nucleus/api/projectlist?format=json" 
var json=JSON.parse(this.responseText);
浏览器中JSON格式的数据如下所示

{
    "1": {
        "id": "91",
        "title": "Nucleus Aura",
        "project_locations": "TVm, Kochi",
        "project_type": "Villa",
        "project_status": "Book Now",
        "count_plan": 0,
        "image": "uploads/project_images/projects_images_image1415954647.png",
        "imagetitle": "Villa Night"
    }
}

我想将JSON数据对象打印到警报框。

将其分配给
var
以获取对象。
如果responseText为

{
    "one": {
        "id": "91",
        "title": "Nucleus Aura",
        "project_locations": "TVm, Kochi",
        "project_type": "Villa",
        "project_status": "Book Now",
        "count_plan": 0,
        "image": "uploads/project_images/projects_images_image1415954647.png",
        "imagetitle": "Villa Night"
    }
}
那么


请澄清你的问题…只是为了确认。。。您正在进行实际的AJAX调用(即使您没有发布代码),对吗?如果没有,您需要进行AJAX调用以使其工作。请使用{}格式化代码!谢谢vikrant,但我没有使用jquery,我想从url var url=“”;var json=json.parse(this.responseText);如果
this.responseText
提供了json字符串,那么您可以将其分配给
var
并发出警报,然后立即测试答案!请再次检查我的问题。。。vikrant对于troublerex很抱歉,当按钮onclick事件发生时,如何添加此代码以执行?你能帮我吗?
getJSON(url, function(json){
    alert(json);// will give output like [object][Object]
    alert(json.one.id);// will give output 91
}
var getJSON = function(url) {
  return new Promise(function(resolve, reject) {
    var xhr = new XMLHttpRequest();
    xhr.open('get', url, true);
    xhr.responseType = 'json';
    xhr.onload = function() {
      var status = xhr.status;
      if (status == 200) {
        resolve(xhr.response);
      } else {
        reject(status);
      }
    };
    xhr.send();
  });
};

var url = "http://nucleus/api/projectlist?format=json";
getJSON(url).then(function(data) {
alert('Your Json result is:  ' + data.result); //you can comment this, i used it to debug

    result.innerText = data.result; //display the result in an HTML element
}, function(status) { //error detection....
alert('Something went wrong.');
});