Javascript 在jQuery选择器中使用函数参数
我有一个名为path的对象,它是:Javascript 在jQuery选择器中使用函数参数,javascript,jquery,Javascript,Jquery,我有一个名为path的对象,它是: var path = { "firstFloor": ["roomA1", "roomA6", "roomA5", "roomA2", "roomA3", "roomA4", "roomA10"], "secondFloor": ["roomB4", "roomB5", "roomB6"], "basementFloor": []} 现在我通常选择阵列(path.firstFloor等),但我需要在一个函数中选择这些对,并将键作为参数,因此: fun
var path = { "firstFloor": ["roomA1", "roomA6", "roomA5", "roomA2", "roomA3", "roomA4", "roomA10"],
"secondFloor": ["roomB4", "roomB5", "roomB6"],
"basementFloor": []}
现在我通常选择阵列(path.firstFloor等),但我需要在一个函数中选择这些对,并将键作为参数,因此:
function draw(floor) { //later on I will call this function with parameter firstFloor
$(path.floor).each(function(i, val){ //this is where I need to select.
var roomIdPath = path.firstFloor[i]
//console.log(roomIdPath);
var points = d3.select('#'+roomIdPath).attr('points').split(",");
var midX = (Number(points[0]) + Number(points[6])) / 2;
var midY = (Number(points[1]) + Number(points[3])) / 2;
floorArray.push({"x": midX, "y": midY});
});
}
不确定我是否清楚,基本上,我所需要的只是在jQuery选择器中使用函数参数的方法。是否仍要执行此操作?如果要向函数发送键,则可以使用键访问映射到对象路径中键的值 当前您使用的是
path.floor
,这是错误的,因为它将在您需要使用的path[floor]
路径对象中查找名为floor的键。您可以这样做:
function draw(floor) { //later on I will call this function with parameter firstFloor
$(path[floor]).each(function(i, val){ //this is where I need to select.
var roomIdPath = path[floor][i];
//console.log(roomIdPath);
var points = d3.select('#'+roomIdPath).attr('points').split(",");
var midX = (Number(points[0]) + Number(points[6])) / 2;
var midY = (Number(points[1]) + Number(points[3])) / 2;
floorArray.push({"x": midX, "y": midY});
});
}
尝试使用括号表示法
path[floor]
,相反,参数将是一个值而不是一个变量,并且不要忘记偶尔使用console.log(variable)
进行调试不确定我的问题是否正确:
您可以迭代元素的键(注意楼层可能是原型中具有其他属性的对象):
或者更好地使用Jquery:
$.each(floors, function(key, value){
//do the thing you were doing in the question
//key is your floor name, value is your array of rooms
});
通常会使用
$.each
而不是$.fn.each
。无需将数组包装在$()
@charlietfl中。您能说出您喜欢的原因吗?因为两者给出相同的结果。可读性是一个<代码>$。每个(数组/obj..显然与dom无关,而$(数组)
与dom无关。同样,内部$(数组)
在内部执行另一个每个
$.each(floors, function(key, value){
//do the thing you were doing in the question
//key is your floor name, value is your array of rooms
});