使用PHP将JSON转换为JavaScript

我是新来的。我的问题是用PHP将JSON转换为JavaScript。我正在使用PHP获取数据库以创建JSON，并希望将JSON转换为JavaScript。我想在JavaScript中使用JSON作为对象（对象[1].id）。我需要你的帮助

    <?php
  $connent = new mysqli('localhost','root','lukasz1248','quiz');
  if ($connent->connect_error != 0)
  {
    throw new Exception(mysqli_connect_errno());
  }
  $connent->query('SET NAMES utf8');
  $connent->query('SET CHARACTER_SET utf8_unicode_ci');
  $result = $connent->query("select * from pytania");

  //put all of the resulting names into a PHP array
  $jsonArray = Array();
  //$how = $result->num_rows;
  //$row = $result->fetch_assoc();

  //$row_array = "[";
  while ($row = $result->fetch_assoc()) {

    $row_array['id'] = $row['id'];
    $row_array['tresc'] = $row['tresc'];
    $row_array['odpa'] = $row['odpa'];
    $row_array['odpb'] = $row['odpb'];
    $row_array['odpc'] = $row['odpc'];
    $row_array['odpd'] = $row['odpd'];
    $row_array['answer'] = $row['answer'];
    $row_array['kategoria'] = $row['kategoria'];
    $row_array['rok'] = $row['rok'];

    array_push($jsonArray,$row_array);
  }
  echo $jsonArray = json_encode($jsonArray,JSON_UNESCAPED_UNICODE);

  $connent->close();
?>
    <script type="text/javascript">
  var json_array = json_encode('<?php echo $jsonArray ?>')

  window.onload = write;

  var obj_json = JSON.parse(json_array);

  function write(){
    document.getElementById('db').innerHTML = obj_json.length;
  }
</script>
<div id="db"></div>

---

我的网站结尾应该是20，你要对它编码两次

第一名

echo $jsonArray = json_encode($jsonArray,JSON_UNESCAPED_UNICODE);
var json_array = json_encode('<?php echo $jsonArray ?>')

echo$jsonArray=json_encode（$jsonArray，json_UNESCAPED_UNICODE）；
var json_array=json_encode（“”）

换成这个

var json_array = <?php echo $jsonArray ?>;

var json_数组=；

已经是Javascript代码，但我们需要将其输出到Javascript中，如下所示

<script type="text/javascript>
    var foo = <?php echo json_encode($bar); ?>;
</script>

---

然后用这个。

我改了。不工作！！！把它改成最后一句话？

var json_array = <?php echo $jsonArray ?>;

<script type="text/javascript>
    var foo = <?php echo json_encode($bar); ?>;
</script>

function getJSON($obj) {
    return '('.json_encode($obj).')';
}