Javascript 角度js语法错误
我对Javascript非常熟悉,因为我在ajax for PHP中使用它,但对AngularJS来说是新手 在我从“tutorialspoint”开始的第一次angularJs作业中,我在控制台中遇到以下错误: 错误:[$injector:moduler] (2)错误。angularjs.angularjs.angularjs.Angulars.2%角度。2.2%棱角。2.2%角度。2.2%角度。文中。angularjs.angularjs.angularjs.2.2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%2%24.GoogleAps.com%2 ajajajajax%2 ajajax.googleapis.com%2 ajajajax%2ff4%2 fLibus%2角度JS2%2 1.3.14%2角度角型(2.2%2角度)1.2%2角型JS1.2%2角型JS1.2角型JS1.1.1.1.2%2角型JS1.1.1.2角型1.1.1.2角型1.1.2角型1.1.2角型1.1.2角型1.1.2角型1.1.1.2角型1.1.2角型1.4.4.2角型。角型。角型(2角型。民。角型(2角型。角型。角型。敏敏。民JS3.2.2角型。民JS3.2.2角型。民JS3.2角型。民JS3.%0As%40https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.3.14%2Fangular.min.js%3A7%3A300%0Ag%40https%3A%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.3.14%2Fangularjs.min.js%3A34%3A399%0Aab%40https%3A%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2Fangularjs%2Fangularjs%2F1.3.14%2Fangularjs%2fa%2Fangularjs%2fa%2fa%2fa%2fam%2Fajax%2fibs%2fagularjs%2F1.3.14%2fagularjs%2fagular.min.js%3A17%3A381%0Atc%40https%3A%2Fajax.googleapis.com%2Fajax%2fibs%2fagularjs%2fagularjs%2fagularjs.14%2fagularjs%2fagularjs%3A18%3A179%0AJd%40https%3A%2Fajax.com%2fajajajax.com%2Fajax%2fagularjs%2fagularjs%2fagularjs%2fagularjs%2F1.3.14%2fagularjs%2fagularjs%2fagularjs%2fagularjs%2fagularjs%2fagularjs%2gular.min.js%3A249%3A428%0Aa%40https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2fanglarjs%2F1.3.14%2fanglarjs.min.js%3A163%3A399%0Alf%2Fc%40https%3A%2F%2Fajax.googleapis.com%2Fajax%2Fajax%2fanglarjs%2F1.3.14%2fanglarjs%3A384%0A 根本不可读 我尝试了Javascript 角度js语法错误,javascript,php,angularjs,Javascript,Php,Angularjs,我对Javascript非常熟悉,因为我在ajax for PHP中使用它,但对AngularJS来说是新手 在我从“tutorialspoint”开始的第一次angularJs作业中,我在控制台中遇到以下错误: 错误:[$injector:moduler] (2)错误。angularjs.angularjs.angularjs.Angulars.2%角度。2.2%棱角。2.2%角度。2.2%角度。文中。angularjs.angularjs.angularjs.2.2%2%2%2%2%2%2%
尝试{}catch(){}
但是没有成功
我无法使用alert()
所以我逐行检查,发现我写了:
var firstApp = angular.module("mainAp", []);
我把data-ng-app
拼错了,应该是mainApp
。
但如果有300行代码,我就无法理解。
所以,我想知道是否有任何简单的方法可以非常明确地显示php中的错误
“[…]根本不可读。”
您正在使用angular的minified angular.min.js版本。这对于生产来说是一件好事(因为文件确实更小),但是如果您想要更可读的错误,可以在开发过程中使用angular.js
举个例子,这就是缩小版的效果:
错误:$injector:moduler模块错误无法实例化模块
mainApp由于以下原因导致:错误:[$injector:modulerr]
$injector/modulerr?p0=e.)
错误(本机)
在
在
在m()
在h()
在
在m()
在h()
对于未统一的版本:
错误:$injector:nomod
模块不可用
模块'ui.bootstrap'
不可用
可获得的您要么拼错了模块名,要么忘记加载它。
如果注册模块,请确保将依赖项指定为
第二个论点
看起来好像未注入$http
。请看。谢谢您的回答。但我仍然认为调试javascript代码很困难