Javascript 如何从NodeJSAPI返回zip文件并在客户端处理？

我有一个API，它使用archiver模块创建一个zip文件，我想在其中将zip作为响应传递回客户端并下载它

这就是我创建zip的API的样子：

reports.get('/xxx/:fileName', async (req, res) => {

  var s3 = new AWS.S3();
  var archiver = require('archiver');

  var filenames = "xxx"
  var str_array = filenames.split(','); 

  for (var i = 0; i < str_array.length; i++) {

    var filename = str_array[i].trim();
    localFileName = './temp/' + filename.substring(filename.indexOf("/") + 1);

    file = fs.createWriteStream(localFileName, {flags: 'a', encoding: 'utf-8',mode: 0666});
    file.on('error', function(e) { console.error(e); });

    s3.getObject({
          Bucket: config.xxx,
          Key: filename
      })
      .on('error', function (err) {
          console.log(err);
      })
      .on('httpData', function (chunk) {
          file.on('open', function(){

            file.write(chunk);
          });
      })
      .on('httpDone', function () {
          file.end();
      })
      .send();
  }
    res.end("Files have been downloaded successfully")

    // create a file to stream archive data to.
    var output = fs.createWriteStream('example.zip');
    var archive = archiver('zip', {
      zlib: { level: 9 } // Sets the compression level.
    });

    // listen for all archive data to be written
    // 'close' event is fired only when a file descriptor is involved
    output.on('close', function() {
      console.log(archive.pointer() + ' total bytes');
      console.log('archiver has been finalized and the output file descriptor has closed.');
    });

    // This event is fired when the data source is drained no matter what was the data source.
    // It is not part of this library but rather from the NodeJS Stream API.
    // @see: https://nodejs.org/api/stream.html#stream_event_end
    output.on('end', function() {
      console.log('Data has been drained');
    });

    // good practice to catch warnings (ie stat failures and other non-blocking errors)
    archive.on('warning', function(err) {
      if (err.code === 'ENOENT') {
        // log warning
      } else {
        // throw error
        throw err;
      }
    });

    // good practice to catch this error explicitly
    archive.on('error', function(err) {
      throw err;
    });

    // pipe archive data to the file
    archive.pipe(output);

    // append files from a sub-directory, putting its contents at the root of archive
    archive.directory('./temp', false);

    // finalize the archive (ie we are done appending files but streams have to finish yet)
    // 'close', 'end' or 'finish' may be fired right after calling this method so register to them beforehand
    archive.finalize();

});

---

如何将zip作为响应发送回客户端并将其下载到磁盘？

由于

archive

是流式传输，我假设它可以通过管道（内衬）直接发送到响应（

res

）：

//Node.js v10+，如果res是正确的流
const{pipeline}=require（'stream'）
管道（存档，res）
//或者（搜索管道与管道的注意事项）
档案.管道（res）

您可能应该在

res

上设置一些HTTP头，以告知浏览器MIME类型以及可能的文件名：

res.set({
“内容类型”：“应用程序/zip”，
“内容处置”：“附件；文件名=“filename.jpg””
})

好的，所以一旦您编写了文件，

example.zip

您就可以轻松地按照中提到的示例进行操作：

---

这应该能很好地发挥作用。归功于

？我明白你的意思，但我该怎么做？用一些例子更新了我的答案。好的，我该如何处理客户端的响应？我通常在响应中使用res.json，但是对于zip来说这应该是不同的。此问题和代码的参考：

reports.get('/xxx/:fileName', async (req, res) => {

  var s3 = new AWS.S3();

  var params = { 
    Bucket: config.reportBucket,
    Key: req.params.fileName,
    Expires: 60 * 5
  }

  try {
    s3.getSignedUrl('getObject', params, function (err, url) {
      if(err)throw err;
      res.json(url);
    });
  }catch (err) {
    res.status(500).send(err.toString());
  }
});

var stat = fileSystem.statSync('example.zip');

res.writeHead(200, {
    'Content-Type': 'application/zip',
    'Content-Length': stat.size
});

var readStream = fileSystem.createReadStream('example.zip');
// We replaced all the event handlers with a simple call to readStream.pipe()
readStream.pipe(res);