Javascript 用JSON数据填充多个选择框
我得到了以下数据库表(尽管数据库中有更多数据,但这还不是全部!):Javascript 用JSON数据填充多个选择框,javascript,jquery,json,Javascript,Jquery,Json,我得到了以下数据库表(尽管数据库中有更多数据,但这还不是全部!): 在PHP和json_encode()的帮助下,我正在创建此表的json字符串: jQuery171024539993586950004_1349776890005([{"0":"0","catid":"0","1":"350","value":"350","2":"350 euro","description":"350 euro"},{"0":"0","catid":"0","1":"500","value":"500",
在PHP和json_encode()的帮助下,我正在创建此表的json字符串:
jQuery171024539993586950004_1349776890005([{"0":"0","catid":"0","1":"350","value":"350","2":"350 euro","description":"350 euro"},{"0":"0","catid":"0","1":"500","value":"500","2":"500 euro","description":"500 euro"},{"0":"0","catid":"0","1":"650","value":"650","2":"650 euro","description":"650 euro"},{"0":"1","catid":"1","1":"0","value":"0","2":"No","description":"No"},{"0":"1","catid":"1","1":"1","value":"1","2":"Yes","description":"Yes"}])
现在,我想使用JSON填充选择框,就像在HTML中一样:
<select id="0">
<option value="350">350 euro</option>
<option value="500">500 euro</option>
<option value="650">650 euro</option>
</select>
<select id="1">
<option value="0">No</option>
<option value="1">Yes</option>
</select>
350欧元
500欧元
650欧元
不
对
有人能帮我吗?我知道如何进行循环来填充表(使用$.getJSON),但我有点受不了这个循环。通过json解析,您应该必须创建一个解析器,并且通过addcat上的if和else条件,您将能够执行此操作。此函数将循环通过您发布的对象并填充菜单(给定您发布的源代码):
var populateSelects=函数(数据){
var cat0=$('select#0'),
cat1=$(“选择#1”),
opt=$(''),
newOpt={},
cat0opts=[],
cat1opts=[];
$。每个(数据、功能(i、obj){
//克隆选项元素,以便不重新创建新元素
newOpt=opt.clone();
//obj是数组中的JavaScript对象,所以
//点表示法工作得很好
newOpt.text(对象描述).val(对象值);
如果(obj.catid==“0”){
//推送DOM元素,而不是jQuery对象
cat0opts.push(newOpt[0]);
}否则如果(obj.catid==“1”){
cat1opts.push(新选项[0]);
}
});
//将DOM元素数组添加到它们各自的菜单中,
//清除所有现有菜单项。
cat0.empty().append(cat0opts);
cat1.empty().append(cat1opts);
};
这里有一把小提琴正在演奏:
重要的一点是
catid
比较。。。如果解析后的JSON以数字(不是字符串)的形式返回catid
,那么您需要将比较更改为if(obj.catid==0)
,通过JSON解析,您应该创建一个解析器,并且通过addcat上的if和else条件,您将能够完成它!非常感谢你花时间写这篇文章。
<select id="0">
<option value="350">350 euro</option>
<option value="500">500 euro</option>
<option value="650">650 euro</option>
</select>
<select id="1">
<option value="0">No</option>
<option value="1">Yes</option>
</select>
var populateSelects = function(data) {
var cat0 = $('select#0'),
cat1 = $('select#1'),
opt = $('<option />'),
newOpt = {},
cat0opts = [],
cat1opts = [];
$.each(data, function(i, obj) {
//clone the option element so as to not re-create a new one
newOpt = opt.clone();
//obj is the JavaScript object in the array, so
//dot-notation works nicely
newOpt.text(obj.description).val(obj.value);
if (obj.catid === "0") {
//push the DOM element, not the jQuery object
cat0opts.push(newOpt[0]);
} else if (obj.catid === "1") {
cat1opts.push(newOpt[0]);
}
});
//Add the array of DOM elements to their respective menus,
//clearing out any existing menu items.
cat0.empty().append(cat0opts);
cat1.empty().append(cat1opts);
};