Javascript mithriljs组件状态未更新为回调或承诺
我使用mithriljs组件状态如下:Javascript mithriljs组件状态未更新为回调或承诺,javascript,mithril.js,Javascript,Mithril.js,我使用mithriljs组件状态如下: const Dashboard = () => { let ExpenseAmount = 0; let IncomeAmount = 0; let UserFullname = ''; const getExpense = () => { ExpenseAmount = 1000; }; const getIncome = () => { IncomeA
const Dashboard = () => {
let ExpenseAmount = 0;
let IncomeAmount = 0;
let UserFullname = '';
const getExpense = () => {
ExpenseAmount = 1000;
};
const getIncome = () => {
IncomeAmount = 2000;
};
const getUserFullname = () => {
setTimeout(() => {
console.log('calling fullname');
UserFullname = 'Mike'; //<----
}, 1000);
}
getUserFullname();
return {
view: () => [
m("div", { class: "container-fluid flex-grow-1 container-p-y" }, [
m(
"h4",
{
class:
"media align-items-center font-weight-bold py-3 mb-4"
},
[
m("img", {
src: "assets/img/avatars/1.png",
class: "ui-w-50 rounded-circle"
}),
m("div", { class: "media-body ml-3" }, [
m("span", `Welcome back, ${UserFullname}!`),
m(
"div",
{ class: "text-muted text-tiny mt-1" },
m(
"small",
{ class: "font-weight-normal" },
`Today is ${new Date().toDateString()}`
)
)
])
]
)
])
]
};
};
const仪表板=()=>{
假设费用金额=0;
设IncomeAmount=0;
让UserFullname='';
const getExpense=()=>{
费用金额=1000;
};
const getIncome=()=>{
IncomeAmount=2000;
};
const getUserFullname=()=>{
设置超时(()=>{
log('calling fullname');
UserFullname='Mike';//[
m(“div”{class:“容器流体flex-grow-1容器-p-y”}[
m(
“h4”,
{
类别:
“媒体对齐项目中心字体粗体py-3 mb-4”
},
[
m(“img”{
src:“assets/img/avatars/1.png”,
类别:“ui-w-50圆形”
}),
m(“div”,{class:“媒体体ml-3}[
m(“span”,“欢迎回来,${UserFullname}!`),
m(
“div”,
{class:“文本静音文本小mt-1”},
m(
“小”,
{class:“字体重量正常”},
`今天是${new Date().toDateString()}`
)
)
])
]
)
])
]
};
};
我希望我可以调用和ajax
函数,并且它的回调/承诺将更新UserFullname
。
但它不起作用。我试着用setTimeout简化它,但仍然不起作用
如何解决ajax调用、priomise或setTimeout中的更新状态
一旦数据发生更改,就要感谢Mithril,因此您需要在函数体的getUserFullname
末尾调用它
您目前拥有:
const getUserFullname = () => {
setTimeout(() => {
UserFullname = 'Mike';
}, 1000);
}
你应该写:
const getUserFullname = () => {
setTimeout(() => {
UserFullname = 'Mike';
m.redraw();
}, 1000);
}