Javascript 如何在按下按钮时获取特定数据
我已经创建了一个搜索页面，根据输入的值给出搜索结果。我想要的是在用户按下注册按钮时获得广告的具体细节。但我得到的是所有广告的详细信息，而不是用户想要注册的广告。 代码如下：Javascript 如何在按下按钮时获取特定数据,javascript,php,jquery,html,Javascript,Php,Jquery,Html,我已经创建了一个搜索页面，根据输入的值给出搜索结果。我想要的是在用户按下注册按钮时获得广告的具体细节。但我得到的是所有广告的详细信息，而不是用户想要注册的广告。 代码如下： <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="css/bootstrap/css/bootstrap.min.css">
<link rel="stylesheet" href="css/font-awesome/css/font-awesome.min.css">
<link rel="stylesheet" href="css/basic.css">
<script src="js/jQuery/jquery.min.js"></script>
<script src="css/bootstrap/js/bootstrap.min.js"></script>
<script src="https://cdn.jsdelivr.net/jquery.validation/1.15.1/jquery.validate.min.js"></script>
<script src="Forms/form-validation.js"></script>
</head>
<body>
<?php
session_start();
require 'connection.php';
//include_once 'utlities.php';
$userEmail=$_SESSION['user'];
$form_string = 'd';
$sqlQuery ='SELECT * FROM `course` WHERE `course_title` LIKE "%'.$form_string.'%" OR `user_teacher` in (SELECT user_teacher FROM teacher where email in (SELECT email from person where fname like "%'.$form_string.'%" OR lname like "%'.$form_string.'%"));';
$queryExe=mysqli_query($connection,$sqlQuery);
$row = mysqli_fetch_assoc($queryExe)
?>
<div class="panel-body">
<?php while($row = mysqli_fetch_assoc($queryExe)) { ?>
<article class="row panel panel-default">
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-sm-offset-0">
<a href="#" title="Lorem ipsum" class="thumbnail"><img src="images/profile-default.jpg" alt="Lorem ipsum" /></a>
</div>
<div class="col-xs-12 col-sm-3">
<ul class="list-group">
<li class="list-group-item">
<i class="glyphicon glyphicon-book"></i>
<span>
<?php
echo " ".$row["description"];
?>
</span>
</li>
<li class="list-group-item">
<i class="glyphicon glyphicon-tags"></i>
<span id="courseid" >
<?php
echo " Course ID ".$row["courseid"];
?>
</span>
</li>
<li class="list-group-item">
<i class="glyphicon glyphicon-tags"></i>
<span>
<?php echo" Rs. ".$row["fees"];
?>
</span>
</li>
</ul>
</div>
<div class="col-xs-12 col-sm-6">
<h3>
<a href="#" title="">
<?php
$sql_profile =
"SELECT `fname`,`lname`,`email`
FROM `person`
WHERE `email`=(
SELECT `email`
FROM `teacher`
WHERE `user_teacher`=".$row["user_teacher"]."
);
";
$result_sql=mysqli_query($connection,$sql_profile);
$tName = mysqli_fetch_assoc($result_sql);
echo $tName["fname"]." ".$tName["lname"];
$_SESSION['temail']= $tName["email"];
?>
</a>
</h3>
<h6><?php echo $tName['email']; ?></h6>
<p class="hidden-xs"><?php echo $row["course_title"]; ?></p>
<span class="plus">
<a href="#" title="Enroll" class="btn btn-success"
<?php
/*if(loggedIn()){
echo 'data-toggle="modal" data-target="#enroll "';
}else{
echo 'data-toggle="modal" data-target="#LOGIN "';
}
/**/
?>>
<i class="glyphicon glyphicon-plus" id="enroll" ></i><span>Enroll</span>
</a>
</span>
</div>
</article>
<?php
}
?>
</div>
<script type="text/javascript">
$(document).ready(function() {
$('#enroll').click(function() {
alert($("article").find("#courseid,h6").text());
});
});
</script>
</body>
</html>
-
-
-
$（文档）.ready（函数（）{
$（“#注册”）。单击（函数（）{
警报（$（“文章”）.find（#courseid，h6”）.text（）；
});
});
data-*.data（）将唯一标识符设置为要显示的内容
<?php
echo "<span id=\"courseid-".$row['courseid']." \" >";
echo " Course ID ".$row["courseid"];
?>
session_start（）已在向页面发送HTML后运行。在您的日志文件中查找已发送的标题
错误您在HTML中使用了重复的ID，因为您使用while循环生成它。ID应该是唯一的。示例：将HTML中的
更改为id应该是唯一的
$('.enroll').click(function() {
var email = $(this).data('email');
var courseid = $(this).data('courseid');
});
<?php
echo "<span id=\"courseid-".$row['courseid']." \" >";
echo " Course ID ".$row["courseid"];
?>
<?php
echo "<i class=\"glyphicon glyphicon-plus\" id=\"enroll\" data-id=\"courseid-".$row["courseid"]." \">";
?>
$('#enroll').click(function() {
courseid = $(this).attr('data-id');
alert($("#"+courseid+",h6").text());
});