Javascript 如何从mongoose find中排除对象数组？

让我们假设我的收藏包含以下元素：

const Item = mongoose.Schema({
   type: { type: String },
   group: { type: Number }
});

[
   { type: "A", group: 1 },
   { type: "B", group: 1 },
   { type: "C", group: 1 },
   { type: "A", group: 2 },
   { type: "B", group: 2 },
   { type: "C", group: 2 },
]

现在我想执行

find

操作，但要排除以下项目：

const items = [
    { type: "A", group: 1 },
    { type: "B", group: 1 },
];

const result = await Model.find({ /* ??? */ });

查询必须如何查看才能获得以下响应

const result = [
   { type: "C", group: 1 },
   { type: "A", group: 2 },
   { type: "B", group: 2 },
   { type: "C", group: 2 },
];

Try运算符，对一个或多个查询表达式的数组执行逻辑“或”操作，并选择数组中所有查询表达式都失败的文档

const items = [
    { type: "A", group: 1 },
    { type: "B", group: 1 },
];
const result = await Model.find({ $nor: items });