如何使用csv文件作为Google Maps JavaScript API的输入

我有这个js代码（这是谷歌地图的一个示例），可以在谷歌地图上构建跟踪。对于4个坐标，这很好，但我想绘制100个坐标的轨迹，手动操作会很痛苦。我该怎么做

function initMap() {

    var map = new google.maps.Map(document.getElementById('map'), {
      zoom: 10,
      center: {lat: 30.20, lng: -97.7},
      mapTypeId: google.maps.MapTypeId.TERRAIN
    });

    var flightPlanCoordinates = [
      {lat: 30.2359091167, lng: -97.7951395833},
      {lat: 30.2691029532, lng: -97.7493953705},
      {lat: 30.2557309927, lng: -97.7633857727},
      {lat: 30.2634181234, lng: -97.7575966669},
      {lat: 30.2742918584, lng: -97.7405226231}
    ];
    var flightPath = new google.maps.Polyline({
      path: flightPlanCoordinates,
      geodesic: true,
      strokeColor: '#FF0000',
      strokeOpacity: 1.0,
      strokeWeight: 2
    });

    flightPath.setMap(map);
  }

---

您可以尝试创建一个函数来将CSV转换为JSON格式吗？i、 e

function csvToJSONCoordinates(data) {
    //Define an empty array for output
    output = [];
    //Split the data by lines
    lines = data.split("\n");
    //For every line recognised
    for(i=0;i<lines.length;i++) {
        //Split the data into latitude and longitude
        coords = lines[i].split(",");
        //Pus these coordinates to the output
        output.push({lat:coords[0], lng:coords[1]});
    }

    //Return the final output
    return output;
}

函数CSVTOJSON坐标（数据）{
//为输出定义一个空数组
输出=[]；
//按行分割数据
行=数据。拆分（“\n”）；
//每行识别
对于（i=0；i很抱歉，我花了一段时间才回到这个问题。我编写了这段代码。我将处理异步数据。这是基于您告诉我它的外观的示例CSV

var dataCSV = 'latitude,longitude\n\
               38.631913,-121.434879\n\
               38.478902,-121.431028\n\
               38.618305,-121.443839\n\
               38.616835,-121.439146\n\
               38.51947,-121.435768\n\
               38.662595,-121.327813\n\
               38.681659,-121.351705\n\
               38.535092,-121.481367\n\
               38.621188,-121.270555\n\
               38.700909,-121.442979\n\
               38.637663,-121.45152\n\
               38.470746,-121.458918\n\
               38.618698,-121.435833\n\
               38.482215,-121.492603\n\
               38.672914,-121.35934\n\
               38.700051,-121.351278\n\
               38.689591,-121.452239\n\
               38.679776,-121.314089\n\
               38.612099,-121.469095\n\
               38.689999,-121.46322\n\
               38.707851,-121.320707\n\
               38.468173,-121.444071\n\
               38.702792,-121.38221\n\
               38.628631,-121.488097\n\
               38.701499,-121.37622\n\
               38.70974,-121.37377\n\
               38.537526,-121.478315\n\
               38.476472,-121.501711\n\
               38.558423,-121.327948\n\
               38.472122,-121.404199\n\
               38.423251,-121.444489\n\
               38.691161,-121.37192\n\
               38.566663,-121.332644\n\
               38.713182,-121.411227\n\
               38.423251,-121.444489\n\
               38.48742,-121.462459\n\
               38.658246,-121.375469\n\
               38.479553,-121.463317\n\
               38.49857,-121.420925\n\
               38.58514,-121.403736\n\
               38.658812,-121.542345\n\
               38.493955,-121.48966\n\
               38.41653,-121.379653\n\
               38.72027,-121.331555\n\
               38.699251,-121.371414\n\
               38.613765,-121.488694\n\
               38.450543,-121.432538';

这是处理CSV文件的函数。您可以通过AJAX将CSV拉入

function processCSV( myCSV ){
    var data = myCSV.split('\n'); // Converts the CSV into an array split on new line.

    /* This will remove the "latitude,longitude" text from the 
     coordinates if it is the top of the CSV file. If it is not at the 
    top then you can leave this out. */
    var dataShift = data.shift();

    var setData = data.map( function( val ) { // maps over the array.
            var latLng = val.split(',');      // splits each value into lat and lng. 
            return {'lat': latLng[0], 'lng': latLng[1] }; //sets the coordinate object.
        });
    return setData; // returns the data.
}

你的CSV看起来像什么？每个坐标在它自己的线上吗？需要知道它看起来像什么来解析它。是的，每个坐标在它自己的线上，纬度和纵向相关问题：