Javascript Phonegap地理位置坐标之间的距离

我试图用javascript计算两个坐标之间的距离。
更具体地说，一组静态坐标和我从地理位置cordova插件获取的当前位置之间的距离

这是我的密码：

document.addEventListener('deviceready', onDeviceReady, false);

function onDeviceReady() {
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};

var onSuccess = function(position) {
    document.getElementById("content").innerHTML = 'Success, attempting calculation...';
    var lla = position.coords.latitude;
    var llo = position.coords.longitude;

    document.getElementById("content").innerHTML =
'GPS Position: ' + calcTheDistance(lla, llo).d + 'Metres';


};

var onError = function(error) {
    document.getElementById("content").innerHTML =
    'code: ' + error.code + '\n' +
    'message: ' + error.message + '\n';
};

function refrGps() {
    document.getElementById("content").innerHTML = 'Loading...';
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};

function calcTheDistance(lati1, long1) {
    var r = 6371000; //Meters
    var joschLat = 50.1109221;
    var joschLon = 8.6821267;
    var la1 = lati1;
    var la2 = joschLat;
    var lat1 = lati1.toRadians();
    var lat2 = joschLat.toRadians();
    var lo1 = long1;
    var lo2 = joschLon;
    var la2minla1 = (la2-la1).toRadians();
    var lo2minlo1 = (lo2-lo1).toRadians();

    var cal = Math.sin(la2minla1 / 2) * Math.sin(la2minla1 / 2) +
            Math.cos(lat1) * Math.cos(lat2) *
            Math.sin(lo2minlo1/2) * Math.sin(lo2minlo1/2);
    var c = 2* Math.atan2(Math.sqrt(cal), Math.sqrt(1-cal));

    d = r * c;
};

我试着重写了好几次，但都没有成功

---

对于我提到的计算：

您引用的页面包含一个。如果在应用程序中包含这些内容，计算将变得微不足道：

document.addEventListener('deviceready', onDeviceReady, false);

function onDeviceReady() {
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};

var onSuccess = function(position) {
    document.getElementById("content").innerHTML = 'Success, attempting calculation...';
    var sourceLl = new LatLon(position.coords.latitude, position.coords.longitude);

    document.getElementById("content").innerHTML =
'GPS Position: ' + calcTheDistance(sourceLl) + 'Metres';
};

var onError = function(error) {
    document.getElementById("content").innerHTML =
    'code: ' + error.code + '\n' +
    'message: ' + error.message + '\n';
};

function refrGps() {
    document.getElementById("content").innerHTML = 'Loading...';
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};

function calcTheDistance(sourceLl) {
    var joschLat = 50.1109221;
    var joschLon = 8.6821267;
    var joschLl = new LatLon(joschLat, joschLon);
    return joschLl.distanceTo(sourceLl);
};

---

所以我在读了@DaveAlden的答案后就明白了，顺便说一句，谢谢

托拉迪亚斯（）；不是一个标准的Javascript函数，所以在我添加了这个函数并重写了一点代码之后，它工作得很好

这是工作代码 文件。添加的监听器（'deviceready'，onDeviceReady，false）

---

问题是什么？它不起作用？给出了错误的结果？你检查过了吗？你发现了吗？：@Koshinae是的，不起作用，它将innerHTML更改为“成功，尝试计算…”，但没有进一步，我没有在

calcTheDistance

中看到

return

语句。我没有使用库，但您的回答认为我的代码有什么问题，非常感谢！

function onDeviceReady() {


navigator.geolocation.getCurrentPosition(onSuccess, onError);
};

var onSuccess = function(position) {
    document.getElementById("content").innerHTML = 'Success, attempting calculation...';
    var lla = position.coords.latitude;
    var llo = position.coords.longitude;
    var dst = 'Distance: ' + calcTheDistance(lla, llo) + ' Metres';
    document.getElementById("content").innerHTML = dst;


};

var onError = function(error) {
    document.getElementById("content").innerHTML =
    'code: ' + error.code + '\n' +
    'message: ' + error.message + '\n';
};

function refrGps() {
    document.getElementById("content").innerHTML = 'Loading...';
    navigator.geolocation.getCurrentPosition(onSuccess, onError);
};

    function toRadians(num) {
        return num * Math.PI / 180; 
};

function calcTheDistance(lati1, long1) {
    var r = 6371000; //metres
    var joschLat = 50.1109221;
    var joschLon = 8.6821267;
    var la1 = lati1;
    var la2 = joschLat;
    var lat1 = toRadians(lati1);
    var lat2 = toRadians(joschLat);
    var lo1 = long1;
    var lo2 = joschLon;
    var la2minla1 = toRadians(la2-la1);
    var lo2minlo1 = toRadians(lo2-lo1);

    var cal = Math.sin(la2minla1 / 2) * Math.sin(la2minla1 / 2) +
            Math.cos(lat1) * Math.cos(lat2) *
            Math.sin(lo2minlo1/2) * Math.sin(lo2minlo1/2);
    var c = 2* Math.atan2(Math.sqrt(cal), Math.sqrt(1-cal));

    var d = r * c;
    return Math.round(d);
};