在不更改日期格式的情况下对日期数组(无前导0)排序Javascript

在不更改日期格式的情况下对日期数组(无前导0)排序Javascript,javascript,arrays,sorting,Javascript,Arrays,Sorting,我有以下日期数组 [ "1/22/20", "1/23/20", "1/24/20", "1/25/20", "1/26/20", "1/27/20", "1/28/20", "1/29/20", "1/30/20", "1/31/20", "2/1/20", "2/10/20", "2/11/20", "2/12/20", "2/13/20", "2/14/20", "2/15/20", "2/16/20", "2/17/20", "2/18/20", "2/19/20", "2/2/20",

我有以下日期数组

[ "1/22/20", "1/23/20", "1/24/20", "1/25/20", "1/26/20", "1/27/20", "1/28/20", "1/29/20", "1/30/20", "1/31/20", "2/1/20", "2/10/20", "2/11/20", "2/12/20", "2/13/20", "2/14/20", "2/15/20", "2/16/20", "2/17/20", "2/18/20", "2/19/20", "2/2/20", "2/20/20", "2/21/20", "2/22/20", "2/23/20", "2/24/20", "2/25/20", "2/26/20", "2/27/20", "2/28/20", "2/29/20", "2/3/20", "2/4/20", "2/5/20", "2/6/20", "2/7/20", "2/8/20", "2/9/20", "3/1/20", "3/2/20", "3/3/20" ]
问题在于,日/月的前导0不是个位数

我想知道是否有某种内置函数可以用来按照正确的顺序对这些日期进行排序,而不是使用一些循环和if语句

下面是一个由于前导0而导致日期不整齐的示例

"1/31/20", "2/1/20", "2/10/20", "2/11/20", "2/12/20", "2/13/20",

编写一个自定义排序函数,将每个日期实例化为一个
date
对象,然后再进行比较

施工日期=[“2/6/20”,“1/23/20”,“1/25/20”,“1/26/20”,“2/16/20”,“1/27/20”,“1/28/20”,“1/29/20”,“1/30/20”,“1/31/20”,“2/1/20/20”,“2/11/20”,“2/12/20”,“2/13/20”,“2/14/20”,“2/15/20”,“2/17/20”,“2/18/20”,“2/19/20”,“2/20”,“2/29/20”,“2/20”,“2/21/20”,“2/21/20”,“2/20”,“2/22/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“2/20”,“,"2/26/20", "2/27/20", "2/28/20", "2/3/20", "2/4/20", "2/5/20", "2/7/20", "2/8/20", "2/9/20", "3/1/20", "3/2/20", "3/3/20" ]; 排序((a,b)=>新日期(a)-新日期(b));
console.log(日期);它们的顺序是否不正确?这是否回答了您的问题?谢谢!这完成了任务!