Javascript中基于用户的对象分组_Javascript_Node.js_Sorting_Grouping

Javascript中基于用户的对象分组

javascript node.js sorting

Javascript中基于用户的对象分组,javascript,node.js,sorting,grouping,Javascript,Node.js,Sorting,Grouping,我正试图根据用户的不同，将从数据库接收到的大量数据分组为单独的对象我得到的数据如下所示： [ { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35', value: 13.450980186462402, created: 2018-05-02T13:21:19.960Z }, { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b

我正试图根据用户的不同，将从数据库接收到的大量数据分组为单独的对象

我得到的数据如下所示：

[ { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:19.960Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:24.179Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:18.249Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:11.230Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 0,
    created: 2018-05-02T11:33:34.705Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:00.049Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:04.269Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:02.365Z }
]

const group = arr.reduce((acc, item) => {
  if (!acc[item.ID]) {
    acc[item.ID] = [];
  }

  acc[item.ID].push(item);
  return acc;
}, {});

const result = Object.values(group);

但我希望函数的输出按相同的ID分组，如下所示

[[{ ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:19.960Z },
{ ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:04.269Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:02.365Z }
],
[
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:18.249Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:11.230Z }
],
[
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:24.179Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 0,
    created: 2018-05-02T11:33:34.705Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:00.049Z }
]]

function groupUserMood(xs, key) {
    return xs.reduce(function(rv, x) {
      (rv[x[key]] = rv[x[key]] || []).push(x);
      return rv;
    }, {});
  };

在javascript中最有效的方法是什么

我找到了一个如下所示的函数

[[{ ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:19.960Z },
{ ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:04.269Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:02.365Z }
],
[
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:18.249Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:11.230Z }
],
[
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:24.179Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 0,
    created: 2018-05-02T11:33:34.705Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:00.049Z }
]]

function groupUserMood(xs, key) {
    return xs.reduce(function(rv, x) {
      (rv[x[key]] = rv[x[key]] || []).push(x);
      return rv;
    }, {});
  };

但这也会将类似的内容添加到一起，这是我不想要的。

使用.reduce按相同的ID分组，然后使用Object.values提取数组：

常量输入=[{ ID:'D4735E3A265E16EEE03F59718B9B5D03019C07D8B6C51F90DA3A66EEC13AB35'，价值：13.450980186462402， }, { ID:'5FECEB66FFC86F38D952786C6D69C79C2DBC239DD4E91B46729D73A27FB57E9'，价值：13.450980186462402， }, { ID:'6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b'，价值：13.450980186462402， }, { ID:'6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b'，价值：13.450980186462402， }, { ID:'5FECEB66FFC86F38D952786C6D69C79C2DBC239DD4E91B46729D73A27FB57E9'，值：0， }, { ID:'5FECEB66FFC86F38D952786C6D69C79C2DBC239DD4E91B46729D73A27FB57E9'，价值：13.450980186462402， }, { ID:'D4735E3A265E16EEE03F59718B9B5D03019C07D8B6C51F90DA3A66EEC13AB35'，价值：13.450980186462402， }, { ID:'D4735E3A265E16EEE03F59718B9B5D03019C07D8B6C51F90DA3A66EEC13AB35'，价值：13.450980186462402， } ]; 常量groupedInputObj=input.ReduceAcum，项=>{ 常量{ID}=项；如果！accum[ID]accum[ID]=[]；累计[ID].pushitem；返回累计； }, {}; 常量输出=Object.valuesgroupedInputObj； console.logoutput 使用.reduce按相同ID分组，然后使用Object.values提取数组：

console.logoutput 您可以这样对它们进行分组：

[ { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:19.960Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:24.179Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:18.249Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:11.230Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 0,
    created: 2018-05-02T11:33:34.705Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:00.049Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:04.269Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:02.365Z }
]

const group = arr.reduce((acc, item) => {
  if (!acc[item.ID]) {
    acc[item.ID] = [];
  }

  acc[item.ID].push(item);
  return acc;
}, {});

const result = Object.values(group);

您所需的结果将在结果变量中。

您可以按如下方式对它们进行分组：

[ { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:19.960Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:24.179Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:18.249Z },
  { ID: '6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:11.230Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 0,
    created: 2018-05-02T11:33:34.705Z },
  { ID: '5feceb66ffc86f38d952786c6d696c79c2dbc239dd4e91b46729d73a27fb57e9',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:00.049Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:04.269Z },
  { ID: 'd4735e3a265e16eee03f59718b9b5d03019c07d8b6c51f90da3a666eec13ab35',
    value: 13.450980186462402,
    created: 2018-05-02T13:21:02.365Z }
]

const group = arr.reduce((acc, item) => {
  if (!acc[item.ID]) {
    acc[item.ID] = [];
  }

  acc[item.ID].push(item);
  return acc;
}, {});

const result = Object.values(group);

您所需的结果将在结果变量中。

保留中间索引的问题可以用不同的方法解决。例如，这样做：

var result = []
var keys = {}
data.forEach(function (e) {
  if (typeof keys[e.ID] === 'undefined') {
    result.push([])
    keys[e.ID] = result.length - 1
  }
  result[keys[e.ID]].push(e)
})

[]

保留中间索引的问题可以用不同的方法解决。例如，这样做：

var result = []
var keys = {}
data.forEach(function (e) {
  if (typeof keys[e.ID] === 'undefined') {
    result.push([])
    keys[e.ID] = result.length - 1
  }
  result[keys[e.ID]].push(e)
})

[]这是无效的语法。创建日期：2018-05-02T13:21:19.960Z}，这是我从Firebase得到的日期。忽略数据值-这不是问题的一部分。这是无效的语法。创建日期：2018-05-02T13:21:19.960Z}，这是我从Firebase得到的日期。忽略数据值-这不是问题的一部分。不幸的是，Object.values在节点6中不可用，只能从节点7及以上。。。有没有办法解决这个问题？我正在考虑执行const output=Object.keysgroupedInputObj.mapfunctionkey{return groupedInputObj[key]；}；但我没有让它工作…不幸的是，Object.values在节点6中不可用，只能从节点7及以上使用。。。有没有办法解决这个问题？我正在考虑执行const output=Object.keysgroupedInputObj.mapfunctionkey{return groupedInputObj[key]；}；但我没有做到这一点……这个解决方案实际上对我来说更有效，因为我使用的是NodeJS，并且Object.values在Node7之前不存在。谢谢这个解决方案实际上对我更有效，因为我使用NodeJS，并且Object.values在Node 7之前不存在。谢谢