Javascript 通过jQuery弹出窗口打开Url
我从google.com上找到了一些代码和源代码 我用Javascript编写了函数Javascript 通过jQuery弹出窗口打开Url,javascript,jquery,popup,Javascript,Jquery,Popup,我从google.com上找到了一些代码和源代码 我用Javascript编写了函数 function a(URL, COORDS, ALT, LINK) { document.write('<AREA SHAPE="poly" '); document.write('id="'+URL+'" href="http://www.domain.com/' + URL); /*This line where you configu
function a(URL, COORDS, ALT, LINK) {
document.write('<AREA SHAPE="poly" ');
document.write('id="'+URL+'" href="http://www.domain.com/' + URL);
/*This line where you configure the output URL, put your domain name address here */
document.writeln('" COORDS="' + COORDS + '" title="' + ALT + '" class="' + LINK + '">')
}
函数a(URL、坐标、ALT、链接){
文件。写('
提前谢谢
<area shape="poly" id="alberta.html" href="http://www.domain.com/alberta.html" coords="114,43" title="" class="">