Javascript 单击时激活按钮切换类
我有这个按钮Javascript 单击时激活按钮切换类,javascript,reactjs,Javascript,Reactjs,我有这个按钮 <ChartButton className={this.state.GPUClicked === 0 ? ' toggled' : ''}onClick={() => this.handleGPUChart(0, 'GPU 1')}>GPU 1</ChartButton> export const ChartButton = styled.button` background-color: #5BB081; border: none
<ChartButton className={this.state.GPUClicked === 0 ? ' toggled' : ''}onClick={() => this.handleGPUChart(0, 'GPU 1')}>GPU 1</ChartButton>
export const ChartButton = styled.button`
background-color: #5BB081;
border: none;
outline: none;
color: white;
padding: 5px 32px;
text-align: center;
text-decoration: none;
display: inline-block;
font-size: 14px;
margin: 4px 2px;
white-space: nowrap;
cursor: pointer;
.toggled {
background-color: #636863;
font-size: 15px;
}
`
这是这个按钮的CSS
<ChartButton className={this.state.GPUClicked === 0 ? ' toggled' : ''}onClick={() => this.handleGPUChart(0, 'GPU 1')}>GPU 1</ChartButton>
export const ChartButton = styled.button`
background-color: #5BB081;
border: none;
outline: none;
color: white;
padding: 5px 32px;
text-align: center;
text-decoration: none;
display: inline-block;
font-size: 14px;
margin: 4px 2px;
white-space: nowrap;
cursor: pointer;
.toggled {
background-color: #636863;
font-size: 15px;
}
`
我错过了什么?我希望按钮在单击时切换,我认为ChartButton组件中的类名是有意义的。我正在为这个扯我的头发。。。提前非常感谢。非常确定,您只需在额外上课之前添加一个(&p):
export const ChartButton = styled.button`
background-color: #5BB081;
border: none;
outline: none;
color: white;
padding: 5px 32px;
text-align: center;
text-decoration: none;
display: inline-block;
font-size: 14px;
margin: 4px 2px;
white-space: nowrap;
cursor: pointer;
&.toggled {
background-color: #636863;
font-size: 15px;
}
`
你的初始状态如何?非常感谢!