Javascript 在angular 2类中存储成员变量的状态

我从服务lamdaService返回一个承诺，其中我将DB中的数据分配给模板/成员变量templateModel，该变量通过template.html中的表单进行修改。我希望初始/旧响应将其与修改后的进行比较，但我没有实现它，因为我启动了新变量旧响应，该响应将使用表单进行更新，并且我在console.log保存功能中得到了相同的结果

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this.oldsresponse=JSON.parse（JSON.stringify（data.excludedRealStateDomains））

对象的深度副本对我来说很有用

this.oldResponse=JSON.parse（JSON.stringify（data.excludedRealStateDomains））

export class RSDLeadsComponent implements OnInit{
    templateModel:RSDLeads  = {
        "excludedRealStateDomains": [{"domain":""}],
        "leadAllocationConfigNotEditables": [{"attributeName":""}]
    };
    oldResponse:any;
    constructor(private lambdaService:LambdaService, @Inject(APP_CONFIG)private config:IAppConfig ){};
    ngOnInit():void{
        this.getFormData();
    };
    getFormData():void{
        let getPayload = {
            "pageId": "DomainLeads",
            "operationType": "view"
        };
        this.lambdaService.getResponse('LAConfigLambda', getPayload).then((data:any) => {
            const tempData = data;
            this.templateModel.excludedRealStateDomains = data.excludedRealStateDomains;     
            this.oldResponse = tempData.excludedRealStateDomains;
        });
    };
    save(model: RSDLeads, isValid: boolean):void{
        console.log("oldResponse",this.oldResponse);//oldResponse [Object, Object, Object]

    console.log("templateModel",this.templateModel.excludedRealStateDomains);//templateModel [Object, Object, Object]
    }
}