Javascript Angular 2-带输入文件的模型驱动表单(文件上载)

Javascript Angular 2-带输入文件的模型驱动表单(文件上载),javascript,angularjs,angular,Javascript,Angularjs,Angular,我目前正在Angular 2中开发一个表单,允许用户更新他的个人资料:电子邮件和密码 user-edit.component.html: <form novalidate="novalidate" [ngFormModel]="form" (ngSubmit)="form.valid && onSubmit()"> <fieldset> <div> <label for="email">

我目前正在Angular 2中开发一个表单,允许用户更新他的个人资料:电子邮件和密码

user-edit.component.html:

<form novalidate="novalidate" [ngFormModel]="form" (ngSubmit)="form.valid && onSubmit()">
    <fieldset>
        <div>
            <label for="email">
                Email
            </label>

            <input id="email" type="email" #email="ngForm" ngControl="email"/>

            <div class="error" *ngIf="email.control.hasError('required') && email.touched">
                This value is required.
            </div>
        </div>

        <div>
            <label for="password">
                Password
            </label>

            <input id="password" type="password" #password="ngForm" ngControl="password"/>

            <div class="error" *ngIf="password.control.hasError('required') && password.touched">
                This value is required.
            </div>
        </div>
    </fieldset>

    <button type="submit" [disabled]="!form.valid">
        Save
    </button>
</form>
user.service.ts:

@Injectable()
export class UserService {
    constructor (
        private _http: Http
    ) {}

    edit(user: User, cfOnNext?: Function, cfOnError?: Function): void {
        let body = JSON.stringify(user);
        let headers = new Headers({
            'Content-Type': 'application/json',
        });
        let options = new RequestOptions({
            headers: headers,
        });

        self._http.put('https://api.dom/me', body, options).subscribe(function (response) {
            if (cfOnNext) {
                cfOnNext(response);
            }
        }, function (response) {
            if (cfOnError) {
                cfOnError(response);
            }
        });
    }
}
今天,我想通过简单地添加一个文件类型字段来允许上传照片

但是我发现关于这个问题的信息很少

我想做的唯一解决办法似乎是:

是否有更好的解决方案来实现这一点?一个更接近我的代码的解决方案,因为我想要最大程度的标准化?例如,我已经使用的$http Angular服务


谢谢

文件在angular2中上载

事实上,
Http
类目前并不支持这一点

您需要利用底层XHR对象来实现这一点:

import {Injectable} from 'angular2/core';
import {Observable} from 'rxjs/Rx';

@Injectable()
export class UploadService {
  constructor () {
    this.progress$ = Observable.create(observer => {
      this.progressObserver = observer
    }).share();
  }

  private makeFileRequest (url: string, params: string[], files: File[]): Observable {
    return Observable.create(observer => {
      let formData: FormData = new FormData(),
        xhr: XMLHttpRequest = new XMLHttpRequest();

      for (let i = 0; i < files.length; i++) {
        formData.append("uploads[]", files[i], files[i].name);
      }

      xhr.onreadystatechange = () => {
        if (xhr.readyState === 4) {
          if (xhr.status === 200) {
            observer.next(JSON.parse(xhr.response));
            observer.complete();
          } else {
            observer.error(xhr.response);
          }
        }
      };

      xhr.upload.onprogress = (event) => {
        this.progress = Math.round(event.loaded / event.total * 100);

        this.progressObserver.next(this.progress);
      };

      xhr.open('POST', url, true);
      xhr.send(formData);
    });
  }
}
从'angular2/core'导入{Injectable};
从'rxjs/Rx'导入{Observable};
@可注射()
导出类上载服务{
构造函数(){
this.progress$=Observable.create(Observable=>{
this.progressObserver=观察者
}).share();
}
私有makeFileRequest(url:string,params:string[],files:File[]):可观察{
返回可观察的。创建(观察者=>{
让formData:formData=new formData(),
xhr:XMLHttpRequest=新的XMLHttpRequest();
for(设i=0;i{
if(xhr.readyState==4){
如果(xhr.status==200){
next(JSON.parse(xhr.response));
observer.complete();
}否则{
观察者错误(xhr响应);
}
}
};
xhr.upload.onprogress=(事件)=>{
this.progress=Math.round(event.loaded/event.total*100);
this.progressObserver.next(this.progress);
};
xhr.open('POST',url,true);
xhr.send(formData);
});
}
}
有关更多详细信息,请参阅此plunkr:

在角回购协议中存在与此相关的问题和未决PR:


答案与(每个单词都是按原样粘贴的)完全相似,为什么不把它标记为副本呢。。是的,是的,因为我认为这个问题和那个问题有些不同,所以把它贴出来作为答案。若你们认为是这样的话,为什么不把它标记为重复的呢。。或者只是在评论中添加一个答案链接。我已经告诉过你,我不认为这个问题与那个问题完全相似,所以不要将这个问题标记为重复。是的,这是我的错,我必须发布链接,而不是回答对不起。嗯,当然,还有很多评论,我用原始答案的链接更新了我的答案。从现在起,我在回答问题时会注意这一点。
import {Injectable} from 'angular2/core';
import {Observable} from 'rxjs/Rx';

@Injectable()
export class UploadService {
  constructor () {
    this.progress$ = Observable.create(observer => {
      this.progressObserver = observer
    }).share();
  }

  private makeFileRequest (url: string, params: string[], files: File[]): Observable {
    return Observable.create(observer => {
      let formData: FormData = new FormData(),
        xhr: XMLHttpRequest = new XMLHttpRequest();

      for (let i = 0; i < files.length; i++) {
        formData.append("uploads[]", files[i], files[i].name);
      }

      xhr.onreadystatechange = () => {
        if (xhr.readyState === 4) {
          if (xhr.status === 200) {
            observer.next(JSON.parse(xhr.response));
            observer.complete();
          } else {
            observer.error(xhr.response);
          }
        }
      };

      xhr.upload.onprogress = (event) => {
        this.progress = Math.round(event.loaded / event.total * 100);

        this.progressObserver.next(this.progress);
      };

      xhr.open('POST', url, true);
      xhr.send(formData);
    });
  }
}