Javascript 将可选函数作为参数传递给另一个函数

如何调用函数的选项：

myAjax("http://ajaxurl.com", { prop: val }, function(resp) { alert(resp); });

if (typeof successFunc == 'function') {
    successFunc(response);
}

或

或

或

我如何在myAjax函数定义中处理这个问题？像这样的东西

function myAjax(url, jsonData, successFunc) {
  $.ajax({
    ... all the necessary ajax stuff that normally goes here
    , success: function(response) {
      // custom myAjax success handling goes here. this must happen before optionally-passed-in successFunc gets executed

      // what goes here? this?
      if (typeof successFunc != 'undefined' && successFunc != null) {
        successFunc(response);
      }
    }
  });
}

我尝试了上面的方法，但是，它没有调用success函数。是否需要检查successFunc是否为函数

---

谢谢

不要针对未知类型进行测试，而是验证该函数确实是一个函数：

myAjax("http://ajaxurl.com", { prop: val }, function(resp) { alert(resp); });

if (typeof successFunc == 'function') {
    successFunc(response);
}

但是，当前代码不会阻止运行

successFunc

。确保成功处理AJAX请求（无错误，无跨域限制）

---

由于您的代码没有达到调用

successFunc

，因此在

if（typeof…

测试typeof successFunc是否为“function”之前可能会生成错误：

function myAjax(url, jsonData, successFunc) {
  $.ajax({
    ... all the necessary ajax stuff that normally goes here
    , success: function(response) {
      // custom myAjax success handling goes here. this must happen before optionally-passed-in successFunc gets executed

      // what goes here? this?
      if (typeof successFunc === 'function') {
        successFunc(response);
      }
    }
  });
}

---

typeof successFunc=='function'

代替或补充？谢谢！

function myAjax(url, jsonData, successFunc) {
  $.ajax({
    ... all the necessary ajax stuff that normally goes here
    , success: function(response) {
      // custom myAjax success handling goes here. this must happen before optionally-passed-in successFunc gets executed

      // what goes here? this?
      if (typeof successFunc === 'function') {
        successFunc(response);
      }
    }
  });
}