试图在JavaScript弹出窗口中传递两个变量

我正在调用下面的脚本，现在我需要能够将两个值发送到

test23.php

like

myFunction20(url,url2) 

有人能帮忙吗

<script>
 function myFunction20(url) {window.open('test23.php?id=' + url, "_blank", "toolbar=no,scrollbars=no,resizable=no,top=70,left=50,width=1200,height=500");}</script>

函数myFunction20（url）{window.open（'test23.php？id='+url，“_blank”，“toolbar=no，scrollbars=no，resizeable=no，top=70，left=50，width=1200，height=500”）；}

PHP代码

echo "<td>" .'<a href= javascript:myFunction20("'.$row['Account_Number'].'","'.$row['Account_Number'].'")>'.$row['Name'].'</a>' . "</td>";

echo“。"";

只需在查询字符串中添加第二个键/值对：

function myFunction20(url) {
    window.open('test23.php?id=' + url + "&SECOND_KEY=" + "SECOND_KEY_VALUE",
    "_blank", 
    "toolbar=no, scrollbars=no, resizable=no, top=70, left=50, width=1200, height=500");
}

---

您应该将PHP变量用引号括起来，并将其传递给JS函数

<?php
  $parameter1 = "'" . $row['Account_Number'] . "'";
  $parameter2 = "'" . $row['Account_Number'] . "'";
  echo 
   '<td>
      <a href= javascript:myFunction20(' . $ip . ',' . $id . ')>' . $row["Name"] . '</a> 
    </td>';

<script>
  function myFunction20(url, url2) {
    window.open('test23.php?id=' + url + '&' + url2, "_blank", "toolbar=no,scrollbars=no,resizable=no,top=70,left=50,width=1200,height=500");
  }

</script>