“显示文本”；“双日”；或；“奇数日”；基于getDay对象的JavaScript_Javascript_Html_Arrays_Date

“显示文本”；“双日”；或；“奇数日”；基于getDay对象的JavaScript

javascript html arrays date

“显示文本”；“双日”；或；“奇数日”；基于getDay对象的JavaScript,javascript,html,arrays,date,Javascript,Html,Arrays,Date,我试图显示文本“偶数天”，当一个月的日期=到2,4,6。。。和“奇数天”，当=1,3,5，等等。我尝试通过一个连接到getDay对象的数组显示文本，但它似乎没有输出任何内容感谢您的帮助进一步实施：好的，我有另一个问题从这里引出。如何每隔一天发送文本“A天”或“B天”，而不管日期是偶数还是奇数这是我的密码： <html> <body> <h2>What day is it?</h2> <p id="demo"></p&g

我试图显示文本“偶数天”，当一个月的日期=到2,4,6。。。和“奇数天”，当=1,3,5，等等。我尝试通过一个连接到getDay对象的数组显示文本，但它似乎没有输出任何内容

感谢您的帮助

进一步实施：
好的，我有另一个问题从这里引出。如何每隔一天发送文本“A天”或“B天”，而不管日期是偶数还是奇数

这是我的密码：

<html>
<body>

<h2>What day is it?</h2>

<p id="demo"></p>

<script>
function myFunction() {
    var time = new Date().getDay();
    var odd = ["1", "3", 

 "5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
    var even = ["2","4",           
 "6","8","10","12","14","16","18","20","22","24","26","28","30"];


if (time = odd) {
        greeting = "Odd Day";
    } else if (time = even) {
        greeting = "Even Day";
document.getElementById("demo").innerHTML = greeting;

</script>

<script type="text/javascript">
    document.write(myFunction())
</script>

</body>
</html>


今天是星期几？

函数myFunction（）{
var time=新日期（）.getDay（）；
变量奇数=[“1”，“3”，
"5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
变量偶数=[“2”，“4”，
"6","8","10","12","14","16","18","20","22","24","26","28","30"];
如果（时间=奇数）{
问候语=“奇数天”；
}否则如果（时间=偶数）{
问候语=“偶数天”；
document.getElementById（“demo”）.innerHTML=问候语；
document.write（myFunction（））

要测试当前日期是偶数还是奇数，您只需测试：

time % 2 != 0  --> ODD

此外，您需要使用：

：根据本地时间返回指定日期的月份日期

函数myFunction（）{
var time=new Date（）.getDate（）；
如果（时间%2！=0）{
问候语=“奇数天”；
}否则{
问候语=“偶数天”；
}
document.getElementById（“demo”）.innerHTML=问候语；
}
myFunction（）；

今天是星期几？

要测试当前日期是偶数还是奇数，您只需测试：

time % 2 != 0  --> ODD

此外，您需要使用：

：根据本地时间返回指定日期的月份日期

函数myFunction（）{
var time=new Date（）.getDate（）；
如果（时间%2！=0）{
问候语=“奇数天”；
}否则{
问候语=“偶数天”；
}
document.getElementById（“demo”）.innerHTML=问候语；
}
myFunction（）；

今天是星期几？

在窗口加载时调用函数，并使用日值的索引检查它是在奇数数组中还是在偶数数组中

<html>
    <head>
    </head>
    <body>
    <h2>What day is it?</h2>
    <p id="demo"></p>
    <script type="text/javascript">
        function myFunction() {
        var time = new Date();
        var day= time.getDay();

    var odd = ["1", "3", 

 "5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
    var even = ["2","4",           
 "6","8","10","12","14","16","18","20","22","24","26","28","30"];


if (odd.indexOf(day)>-1) {
        greeting = "Odd Day";
    } 
    else  {
        greeting = "Even Day";
document.getElementById("demo").innerHTML = greeting;
}
}
</script>

<script type="text/javascript">
 window.onload= myFunction();
</script>
</body>
</html>


今天是星期几？

函数myFunction（）{
变量时间=新日期（）；
var day=time.getDay（）；
变量奇数=[“1”，“3”，
"5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
变量偶数=[“2”，“4”，
"6","8","10","12","14","16","18","20","22","24","26","28","30"];
if（奇数指数（天）>-1）{
问候语=“奇数天”；
} 
否则{
问候语=“偶数天”；
document.getElementById（“demo”）.innerHTML=问候语；
}
}
window.onload=myFunction（）；

在窗口加载时调用函数，并使用日值的索引检查它是在奇数数组中还是在偶数数组中

<html>
    <head>
    </head>
    <body>
    <h2>What day is it?</h2>
    <p id="demo"></p>
    <script type="text/javascript">
        function myFunction() {
        var time = new Date();
        var day= time.getDay();

    var odd = ["1", "3", 

 "5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
    var even = ["2","4",           
 "6","8","10","12","14","16","18","20","22","24","26","28","30"];


if (odd.indexOf(day)>-1) {
        greeting = "Odd Day";
    } 
    else  {
        greeting = "Even Day";
document.getElementById("demo").innerHTML = greeting;
}
}
</script>

<script type="text/javascript">
 window.onload= myFunction();
</script>
</body>
</html>


今天是星期几？

函数myFunction（）{
变量时间=新日期（）；
var day=time.getDay（）；
变量奇数=[“1”，“3”，
"5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
变量偶数=[“2”，“4”，
"6","8","10","12","14","16","18","20","22","24","26","28","30"];
if（奇数指数（天）>-1）{
问候语=“奇数天”；
} 
否则{
问候语=“偶数天”；
document.getElementById（“demo”）.innerHTML=问候语；
}
}
window.onload=myFunction（）；

正如@DavidG所指出的，您使用表格是错误的

您需要使用for循环，依次将date-day值与表中的每个元素进行比较

为什么要使用查找表？检查均匀度的正确方法是：

var day = new Date().getDay();
if ((day & 1) == 0)
{
   greetings = "even";
}
else
{
   greetings = "odd";
}

正如@DavidG指出的那样，您使用表格是错误的

您需要使用for循环，依次将date-day值与表中的每个元素进行比较

为什么要使用查找表？检查均匀度的正确方法是：

var day = new Date().getDay();
if ((day & 1) == 0)
{
   greetings = "even";
}
else
{
   greetings = "odd";
}

实际上，您的代码很好，只需关闭花括号。要检查数字是否在数组中，请使用

array.includes（value）

即可

    <html>
    <body>

    <h2>What day is it?</h2>

    <p id="demo"></p>

    <script>
    function myFunction() {
    var time = new Date().getDay();
    var odd = ["1", "3", 

 "5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
    var even = ["2","4",           
 "6","8","10","12","14","16","18","20","22","24","26","28","30"];
checknum = odd.includes(time);

if (checknum == true) {
        greeting = "Odd Day";
    } else {
        greeting = "Even Day";
}
//document.getElementById("demo").innerHTML = greeting;
console.log(time);
console.log(checknum);
console.log(greeting);
}

    </script>

    <script type="text/javascript">
        document.write(myFunction())
    </script>

    </body>
    </html>


今天是星期几？

函数myFunction（）{
var time=新日期（）.getDay（）；
变量奇数=[“1”，“3”，
"5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
变量偶数=[“2”，“4”，
"6","8","10","12","14","16","18","20","22","24","26","28","30"];
checknum=奇数。包括（时间）；
if（checknum==true）{
问候语=“奇数天”；
}否则{
问候语=“偶数天”；
}
//document.getElementById（“demo”）.innerHTML=问候语；
console.log（时间）；
console.log（checknum）；
控制台日志（问候语）；
}
document.write（myFunction（））

现在它可以正常工作了

希望这有助于…！

实际上，您的代码很好，只需关闭花括号。要检查数字是否在数组中，请使用

array。includes（value）

它会很好地工作

    <html>
    <body>

    <h2>What day is it?</h2>

    <p id="demo"></p>

    <script>
    function myFunction() {
    var time = new Date().getDay();
    var odd = ["1", "3", 

 "5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
    var even = ["2","4",           
 "6","8","10","12","14","16","18","20","22","24","26","28","30"];
checknum = odd.includes(time);

if (checknum == true) {
        greeting = "Odd Day";
    } else {
        greeting = "Even Day";
}
//document.getElementById("demo").innerHTML = greeting;
console.log(time);
console.log(checknum);
console.log(greeting);
}

    </script>

    <script type="text/javascript">
        document.write(myFunction())
    </script>

    </body>
    </html>


今天是星期几？

函数myFunction（）{
var time=新日期（）.getDay（）；
变量奇数=[“1”，“3”，
"5","7","9","11","13","15","17","19","21","23","25","27","29","31"];
变量偶数=[“2”，“4”，
"6","8","10","12","14","16","18","20","22","24","26","28","30"];
checknum=奇数。包括（时间）；
if（checknum==true）{
问候语=“奇数天”；
}否则{
问候语=“偶数天”；
}
//document.getElementById（“demo”）.innerHTML=问候语；
console.log（时间）；
console.log（checknum）；
控制台日志（问候语）；
}
document.write（myFunction（））

现在它可以正常工作了

希望这有帮助……！

您的功能没有被

关闭，您的

else

语句也没有被

关闭

getDay（）

返回一周中的哪一天。您需要

.getDate（）

返回周一的日期