Javascript 对对象数组中的重复项进行计数,并对对象中的值求和
我有一个如下所示的对象数组:Javascript 对对象数组中的重复项进行计数,并对对象中的值求和,javascript,node.js,arrays,Javascript,Node.js,Arrays,我有一个如下所示的对象数组: const users = [{name: 'John', gender: 'Male', orders: 20}, {name: 'Doe', gender: 'Male', orders: 8}, {name: 'Ada', gender: 'Female', orders: 10}, {name: 'David', gender: 'Male', orders: 30}]; [{gender: 'Male', count: 3, to
const users = [{name: 'John', gender: 'Male', orders: 20},
{name: 'Doe', gender: 'Male', orders: 8},
{name: 'Ada', gender: 'Female', orders: 10},
{name: 'David', gender: 'Male', orders: 30}];
[{gender: 'Male', count: 3, totalOrders: 58}, {gender: 'Female', count: 1, totalOrders: 10}]
我需要计算重复性别的数量,并根据对象中的性别总结订单数量。我希望最终的数组如下所示:
const users = [{name: 'John', gender: 'Male', orders: 20},
{name: 'Doe', gender: 'Male', orders: 8},
{name: 'Ada', gender: 'Female', orders: 10},
{name: 'David', gender: 'Male', orders: 30}];
[{gender: 'Male', count: 3, totalOrders: 58}, {gender: 'Female', count: 1, totalOrders: 10}]
这是我目前掌握的代码:
const usersGender = users.map((user) => user.gender);
const result = Object.values(usersGender.reduce((a, b) => {
a[b] = a[b] || [b, 0];
a[b][1]++;
return a;
},{})).map(item => ({gender: item[0], count : item[1]}));
console.log(result);
以上代码的输出是:
[{ gender: 'Male', count: 3 }, { gender: 'Female', count: 1 }]
谢谢。您可以使用对象进行收集并从中获取值 常数 用户=[{name:'John',gender:'Male',orders:20},{name:'Doe',gender:'Male',orders:8},{name:'Ada',gender:'femal',orders:10},{name:'David',gender:'Male',orders:30}], 结果=Object.valuesusers.reducer,{性别,顺序}=>{ r[gender]??={gender,count:0,totalOrders:0}; r[gender].count++; r[性别]。总订单+=订单; 返回r; }, {}; console.logresult;
.as console wrapper{max height:100%!important;top:0;}您可以使用对象进行收集并从中获取值 常数 用户=[{name:'John',gender:'Male',orders:20},{name:'Doe',gender:'Male',orders:8},{name:'Ada',gender:'femal',orders:10},{name:'David',gender:'Male',orders:30}], 结果=Object.valuesusers.reducer,{性别,顺序}=>{ r[gender]??={gender,count:0,totalOrders:0}; r[gender].count++; r[性别]。总订单+=订单; 返回r; }, {}; console.logresult; .作为控制台包装{最大高度:100%!重要;顶部:0;}