Javascript Redux表单:如何处理表单组件中的错误
现在我有这样的错误:Javascript Redux表单:如何处理表单组件中的错误,javascript,reactjs,promise,redux-form,Javascript,Reactjs,Promise,Redux Form,现在我有这样的错误: Unhandled Rejection (SubmissionError): Submit Validation Failed 27 | .catch(err => { > 28 | return ErrorHandler.raiseAnError(err); 29 | }); 这是我的密码: TractorForm.js import React, { Component } from "react"; im
Unhandled Rejection (SubmissionError): Submit Validation Failed
27 | .catch(err => {
> 28 | return ErrorHandler.raiseAnError(err);
29 | });
这是我的密码:
TractorForm.js
import React, { Component } from "react";
import PropTypes from "prop-types";
import { reduxForm } from "redux-form";
import FormInput from "../Shared/FormInput";
import GlobalConst from "../GlobalConst";
import { Link } from "react-router-dom";
import SelectInput from "../Shared/SelectInput";
import ErrorHandler from "../ErrorHandler";
const manufacturers = ["DAF", "VOLVO", "SCANIA", "MAN", "IVECO"];
class TractorFormWrapper extends Component {
state = {
loading: false,
isSubmitted: false
};
onFormSubmit = e => {
e.preventDefault();
this.setState({ isSubmitted: true });
if (this.props.valid) {
this.setState({ loading: true });
this.props
.handleSubmit(e)
.then(() => alert("is ok!"))
.catch(err => {
return ErrorHandler.raiseAnError(err);
});
}
};
render() {
const { submitText, error } = this.props;
const { loading, isSubmitted } = this.state;
const formClassNames = loading ? "ui form loading" : "ui form";
return (
<form className={formClassNames} onSubmit={this.onFormSubmit}>
<div className="ui grid fields">
<div className="sixteen wide eight wide computer column">
<SelectInput
name="manufacturer"
type="text"
label="Производитель"
validations={[GlobalConst.REQUIRED]}
isSubmitted={isSubmitted}
values={manufacturers}
/>
</div>
<div className="sixteen wide eight wide computer column">
<FormInput
name="model"
type="text"
label="Модель"
validations={[GlobalConst.REQUIRED]}
isSubmitted={isSubmitted}
/>
</div>
<div className="sixteen wide column">
<FormInput
name="description"
type="textarea"
label="Описание"
isSubmitted={isSubmitted}
/>
</div>
</div>
{error && (
<div className="ui red message">
<strong>{error}</strong>
</div>
)}
<div className="ui fluid buttons">
<button
className="ui primary button"
type="submit"
disabled={loading}
>
{submitText}
</button>
<Link to="/tractors" className="ui button">
Отмена
</Link>
</div>
</form>
);
}
}
let TractorForm = {};
TractorForm.propTypes = {
submitText: PropTypes.string
};
TractorForm.defaultProps = {
submitText: "Отправить"
};
TractorForm = reduxForm({
form: "tractor"
})(TractorFormWrapper);
export default TractorForm;
import React, { Component } from "react";
import TractorForm from "./TractorForm";
import TractorApi from "./TractorApi";
import { toast } from "react-semantic-toasts";
import ErrorHandler from "../ErrorHandler";
class TractorAdd extends Component {
state = {};
submit = values =>
TractorApi.create(values).then(
() => {
toast({
type: "success",
icon: "truck",
title: "Тягач создан",
description: ""
});
this.props.history.push("/tractors");
},
error => {
return Promise.reject(error);
}
);
render() {
return (
<div>
<TractorForm onSubmit={this.submit} submitText="Создать" />
</div>
);
}
}
export default TractorAdd;
import { SubmissionError } from "redux-form";
export default {
raiseAnError: error => {
if (
error.response.data.hasOwnProperty("message") &&
error.response.data.hasOwnProperty("stackHighlighted")
) {
throw new SubmissionError({
_error: error.response.data.hasOwnProperty("message") || "error"
});
} else {
const errKeys = Object.keys(error.response.data);
const errObj = {};
for (const errItem of errKeys) {
errObj[errItem] = error.response.data[errItem]["message"];
}
errObj["_error"] = "Произошла ошибка!";
throw new SubmissionError(errObj);
}
}
};
为什么我需要这个表单而不是添加组件?所以我可以用加载状态变量来修复逻辑,然后重新提交表单
另外,由于某些原因,我的\u错误
不起作用,但我已经完成了文档中的所有操作:
我做错了什么以及如何处理表单组件中的SubmissionError?错误处理不起作用的原因是您应该在handleSubmit
函数本身中抛出新的SubmissionError
:
更新2-保持实现原样,但稍微更改一下您的TractorFormWrapper
onFormSubmit
及其用法:
文件说明
TractorForm
class TractorFormWrapper extends Component {
state = {
loading: false,
isSubmitted: false
};
onFormSubmit = data => {
this.setState({ isSubmitted: true });
if (this.props.valid) {
this.setState({ loading: true });
// `onSubmit` comes from `TractorAdd`
return this.props.onSubmit(data)
.then(() => alert("is ok!"))
.catch(err => {
return ErrorHandler.raiseAnError(err);
});
}
};
render() {
const { handleSubmit } = this.props
return <form onSubmit={handleSubmit(this.onFormSubmit)}>The rest logic is here ...</form>
}
}
let TractorForm = {};
TractorForm.propTypes = {
submitText: PropTypes.string
};
TractorForm.defaultProps = {
submitText: "Отправить"
};
TractorForm = reduxForm({
form: "tractor"
})(TractorFormWrapper);
export default TractorForm;
类TractorFormWrapper扩展组件{
状态={
加载:false,
提交的问题:错误
};
onFormSubmit=数据=>{
this.setState({isSubmitted:true});
if(this.props.valid){
this.setState({loading:true});
//“onSubmit”来自“tractorad”`
返回此.props.onSubmit(数据)
。然后(()=>警报(“正常!”)
.catch(错误=>{
返回ErrorHandler.raiseAnError(err);
});
}
};
render(){
const{handleSubmit}=this.props
返回剩余的逻辑在这里。。。
}
}
设TractorForm={};
TractorForm.propTypes={
submitText:PropTypes.string
};
TractorForm.defaultProps={
提交文本:“ааааааа”
};
TractorForm=reduxForm({
表格:“拖拉机”
})(拖拉机式包装机);
导出默认TractorForm;
ok,但是如何this.props.handleSubmit(e).then(()=>alert(“is ok!”)).catch(err=>{return ErrorHandler.raiseAnError(err);})代码>在这里陷入困境?这也是一个非常糟糕的主意:在表单组件中编辑和添加相同的代码表单:这就是为什么我使用formAdd
组件和“嵌套的”form
组件:表单是隔离的,服务器调用是在另一个逻辑组件中添加的。这几乎是一个完整的示例。请按照我回答的反馈意见和我为您提供的示例进行操作。谢谢,但您仍然缺少一个非常重要的部分:handleSubmit
未在表单组件中重新定义=>我无法添加ui微调器加载程序和禁用按钮。onFormSubmit=e=>{e.preventDefault();this.setState({issubmitt:true});//因此,只有当(this.props.valid){//表单有效时,我才能在单击提交按钮时显示错误消息。让我们将其发送到服务器,而不是当this.setState({loading:true})无效时;//让我们显示微调器this.props.handleSubmit(e)。然后(()=>警报(“ok!”)//在这里,我们必须隐藏微调器,不做任何其他事情……捕获(err=>{return ErrorHandler.raiseAnError(err);//这里我们必须隐藏微调器,并在将来需要时执行其他操作,但它总是进入。然后阻塞:()};};
例如:如果我写error=>{throw new error({});}
-一切都很好,然后形成组件().catch()转到catch block,但当我使用SubmissionError时,它会转到then(就像promise是可以的,但它不是!)
<form className={formClassNames} onSubmit={handleSubmit(values => {
// 1. Your submit logic should be here.
// 2. Better to organize it in a stand-alone function, as `submit` function from the above example.
// 3. If you throw SubmissionError here, the error handling will work.
throw new SubmissionError({
_error: 'Error'
})
)}>
class TractorForm extends Component {
render() {
const { handleSubmit, error } = this.props;
return (
<form onSubmit={handleSubmit}>
// Rest input fields should be here ...
{ error && (
<div className="ui red message">
<strong>{error}</strong>
</div>
)}
<div className="ui fluid buttons">
<button
className="ui primary button"
type="submit"
disabled={loading}
>
{submitText}
</button>
</div>
</form>
);
}
}
export default reduxForm({
form: "tractor"
})(TractorForm);
class TractorAdd extends Component {
onSubmit (values) {
// Please make sure here you return the promise result. It's a `redux-form` gotcha.
// If you don't return it, error handling won't work.
return TractorApi.create(values).then(
() => {
toast({
type: "success",
icon: "truck",
title: "Тягач создан",
description: ""
});
this.props.history.push("/tractors");
},
error => {
// 1. Here you should throw new SubmissionError.
// 2. You should normalize the error, using some parts of `ErrorHandler` function
throw new SubmissionError(error)
}
);
}
render() {
return <div>
<TractorForm onSubmit={this.onSubmit} submitText="Создать" />
</div>
}
}
export default TractorAdd;
class TractorFormWrapper extends Component {
state = {
loading: false,
isSubmitted: false
};
onFormSubmit = data => {
this.setState({ isSubmitted: true });
if (this.props.valid) {
this.setState({ loading: true });
// `onSubmit` comes from `TractorAdd`
return this.props.onSubmit(data)
.then(() => alert("is ok!"))
.catch(err => {
return ErrorHandler.raiseAnError(err);
});
}
};
render() {
const { handleSubmit } = this.props
return <form onSubmit={handleSubmit(this.onFormSubmit)}>The rest logic is here ...</form>
}
}
let TractorForm = {};
TractorForm.propTypes = {
submitText: PropTypes.string
};
TractorForm.defaultProps = {
submitText: "Отправить"
};
TractorForm = reduxForm({
form: "tractor"
})(TractorFormWrapper);
export default TractorForm;