Jpa java.lang.IllegalStateException:没有显式选择,无法确定隐式选择
下面是我的jpa代码Jpa java.lang.IllegalStateException:没有显式选择,无法确定隐式选择,jpa,Jpa,下面是我的jpa代码 CriteriaBuilder cb = entityManager.getCriteriaBuilder(); CriteriaQuery cq = cb.createQuery(); Root e = cq.from(Student.class); cq.where(cb.greaterThan(e.get("id"), 3)); Query query = entityManager.createQuery(cq); L
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery cq = cb.createQuery();
Root e = cq.from(Student.class);
cq.where(cb.greaterThan(e.get("id"), 3));
Query query = entityManager.createQuery(cq);
List<Student> students = query.getResultList();
CriteriaBuilder cb=entityManager.getCriteriaBuilder();
CriteriaQuery cq=cb.createQuery();
根e=cq.from(学生班级);
cq.where(cb.greaterThan(e.get(“id”),3));
Query Query=entityManager.createQuery(cq);
List students=query.getResultList();
我想得到所有id大于3的学生。
谢谢。我想您必须定义将从表中选择的列
CriteriaBuilder cb = entityManager.getCriteriaBuilder();
CriteriaQuery<Student> cq = cb.createQuery(Student.class);
Root<Student> root = cq.from(Student.class);
cq.where(cb.greaterThan(e.get("id"), 3));
cq.select(root); // Which columns will be selected? Presuming all.
List<Student> studentList = entityManager.createQuery(cq).getResultList();
CriteriaBuilder cb=entityManager.getCriteriaBuilder();
CriteriaQuery cq=cb.createQuery(Student.class);
Root Root=cq.from(学生班级);
cq.where(cb.greaterThan(e.get(“id”),3));
cq.选择(根);//将选择哪些列?假定所有的。
List studentList=entityManager.createQuery(cq.getResultList();