Jquery 使用$.each进行迭代时
在遍历包含数据的对象时,我检查image的url是否对函数有效。问题是,函数检查映像只对最后一个对象运行了8次。谁都知道为什么 功能检查图像:Jquery 使用$.each进行迭代时,jquery,iteration,each,Jquery,Iteration,Each,在遍历包含数据的对象时,我检查image的url是否对函数有效。问题是,函数检查映像只对最后一个对象运行了8次。谁都知道为什么 功能检查图像: function checkImage(url, succ, err){ var checkImg = new Image(); checkImg.src = url; checkImg.onerror = function() { err(); }; } 以及每一部分: var obj = {}, se
function checkImage(url, succ, err){
var checkImg = new Image();
checkImg.src = url;
checkImg.onerror = function() {
err();
};
}
以及每一部分:
var obj = {},
searchResults = [];
$.each(data, function(i, m){
obj = {'image': m.park_photo1_290x220, 'name': m.park_name, 'developer': m.park_developer_name,
'location': m.park_location_name, 'exact_location': m.park_location_parent_name,
'total_area': m.area, 'free_area': m.free_area, 'id': m.id, 'lat': m.park_lat, 'lon': m.park_lon};
var uri = obj.image;
console.log('object');
checkImage(uri, function(){
obj.image = uri;
}, function() {
console.log(x++);
console.log(obj.name+','+obj.image);
obj.image = 'images/no_foto_ssmall.png';
console.log(obj.image);
});
searchObjects.push(obj);
$('#search-results').append(''+
'<li class=\"ui-li-has-thumb ui-btn ui-btn-icon-right ui-li ui-btn-up-c\" role=\"option\" tabindex=\"'+ i +'\" data-theme=\"c\"><div>'+
'<img src=\"'+ searchObjects[i].image +'\" class="ui-li-thumb">'+
'<h3 class="ui-li-heading"><a href="#" class="ui-link-inherit single" name=\"'+ i +'\">'+
searchObjects[i].name +'</a></h3></div>'+
'<div class=\"search-detail\"><p>'+ searchObjects[i].developer +'</p></div>'+
'<div class=\"search-detail\"><p>'+ searchObjects[i].location +'</p></div>'+
'<span class=\"ui-icon ui-icon-arrow-r\"></span></li>'
);
});
o_foto_ssmall.png
图片/否\u foto\u ssmall.png
编辑 应要求,我的目标是:
var data = [{"total_area": 10800.0, "developer_id": 1511,
"photo1_290x220": "/static/realestate/wp/wpp176885389187907.jpg.290x220_q85.jpg",
"location_parent_name": "BZZ", "agent_phone_fax": "",
"location_id": 147, "id": 760, "developer_fax": "", "location_name": "ABC",
"lon": 10.870075199999999, "object_id": 201, "developer_name": "Orpo",
"agent_id": 8,"lat": 52.2079223, "warehouses_counter": 1,
"name": "Park 1","agent_phone_mobile": "+48 668 124 152", "featured": false,
"location_parent_id": 106},
{"total_area": 30780.0, "developer_id": 193,
"photo1_290x220": "/static/realestate/wp/wpp195908774409312.JPG.290x220_q85.jpg",
"location_parent_name": "CDE", "agent_phone_fax": "", "location_id": 138,
"id": 761, "developer_fax": "", "location_name": "XYZ",
"lon": 20.9232473, "object_id": 187, "developer_name": "Orco","lat": 32.171918300000002,
"warehouses_counter": 5, "name": "Park 2","featured": false,
"location_parent_id": 106}]
所有闭包都在相同的范围内关闭,因此相同的
obj
实例在调用obj
时异步调用onerror
解决方案应该是在obj
之前添加var
:
var obj = {'image': ...
这将执行两次相同的代码,一次使用修复程序,一次不使用修复程序。看起来您的变量
obj
定义超出了范围,因此无法正确计算
可能searchResults
变量应该是searchObjects
1
它看起来像是你试图从散列中读取不正确的数据,所以它几乎在任何地方都返回undefined
My be此代码可以帮助您:
var x = 0;
var obj = {},
searchObjects = [];
$.each(data, function(i, m){
var obj1 = {'image': m.photo1_290x220, 'name': m.name, 'developer': m.developer_name,
'location': m.location_name, 'exact_location': m.location_parent_name,
'total_area': m.total_area, 'free_area': m.free_area, 'id': m.id, 'lat': m.lat, 'lon': m.lon};
var uri = obj1.image;
console.log(obj1.name+','+obj1.image);
checkImage(uri, function(){
obj1.image = uri;
}, function() {
console.log(x++);
obj1.image = 'images/no_foto_ssmall.png';
console.log(obj1.image);
});
searchObjects.push(obj1);
$('#search-results').append(''+
'<li class=\"ui-li-has-thumb ui-btn ui-btn-icon-right ui-li ui-btn-up-c\" role=\"option\" tabindex=\"'+ i +'\" data-theme=\"c\"><div>'+
'<img src=\"'+ searchObjects[i].image +'\" class="ui-li-thumb">'+
'<h3 class="ui-li-heading"><a href="#" class="ui-link-inherit single" name=\"'+ i +'\">'+
searchObjects[i].name +'</a></h3></div>'+
'<div class=\"search-detail\"><p>'+ searchObjects[i].developer +'</p></div>'+
'<div class=\"search-detail\"><p>'+ searchObjects[i].location +'</p></div>'+
'<span class=\"ui-icon ui-icon-arrow-r\"></span></li>'
);
});
var x=0;
var obj={},
searchObjects=[];
$。每个(数据、函数(i、m){
var obj1={'image':m.photo1_290x220,'name':m.name,'developer':m.developer_name,
“位置”:m.location\u name,“精确位置”:m.location\u parent\u name,
“总面积”:m.total_area,“free_area”:m.free_area,“id”:m.id,“lat”:m.lat,“lon”:m.lon};
var uri=obj1.image;
console.log(obj1.name+','+obj1.image);
checkImage(uri,函数(){
obj1.image=uri;
},函数(){
console.log(x++);
obj1.image='images/no_foto_ssmall.png';
console.log(obj1.image);
});
searchObjects.push(obj1);
$('#搜索结果')。附加(''+
“”右侧有拇指ui btn ui btn图标+
''+
''+
“”+searchObjects[i].开发者+”'+
“”+searchObjects[i]。位置+”'+
“ ”
);
});
这是在fiddler上收集的数据对象是什么样子的?不,这并没有解决任何问题。我在上面声明了var obj.each();以后附件也能正常工作。好的,你说得对,对不起。我在控制台里玩得太多了。必须解决异步问题,并且一切正常:)
var x = 0;
var obj = {},
searchObjects = [];
$.each(data, function(i, m){
var obj1 = {'image': m.photo1_290x220, 'name': m.name, 'developer': m.developer_name,
'location': m.location_name, 'exact_location': m.location_parent_name,
'total_area': m.total_area, 'free_area': m.free_area, 'id': m.id, 'lat': m.lat, 'lon': m.lon};
var uri = obj1.image;
console.log(obj1.name+','+obj1.image);
checkImage(uri, function(){
obj1.image = uri;
}, function() {
console.log(x++);
obj1.image = 'images/no_foto_ssmall.png';
console.log(obj1.image);
});
searchObjects.push(obj1);
$('#search-results').append(''+
'<li class=\"ui-li-has-thumb ui-btn ui-btn-icon-right ui-li ui-btn-up-c\" role=\"option\" tabindex=\"'+ i +'\" data-theme=\"c\"><div>'+
'<img src=\"'+ searchObjects[i].image +'\" class="ui-li-thumb">'+
'<h3 class="ui-li-heading"><a href="#" class="ui-link-inherit single" name=\"'+ i +'\">'+
searchObjects[i].name +'</a></h3></div>'+
'<div class=\"search-detail\"><p>'+ searchObjects[i].developer +'</p></div>'+
'<div class=\"search-detail\"><p>'+ searchObjects[i].location +'</p></div>'+
'<span class=\"ui-icon ui-icon-arrow-r\"></span></li>'
);
});