Jquery 如何在更改dropdownlist时获取动态表行

嗨，当我选择下拉列表时，我正在尝试获取表格行。这是我的密码，请帮帮我。你好，鲁比对不起，首先我对这个问题理解错了。。试试这个

    $.ajax({
    type: 'GET',
    url: "/HostingProject/SIPAdminCustServlet",
    data: {ActionType:"1",userID:userID },
    success:function(responseJson){

    var tbody = $("#Account");
    alert("JSonResponse: "+responseJson);
    $.each(responseJson, function(index, account) {    // Iterate over the JSON array.
    var value = ATYpeMap[account.AccountTypeID];
     $('<tr>').appendTo(tbody)                     // Create HTML <tr> element, set its     text content with currently iterated item and append it to the <table>.
    .append($('<td>').text(account.AccountNumber))        // Create HTML <td> element, set its text content with id of currently iterated account and append it to the <tr>.
     .append($('<td>').text(value))        // Create HTML <td> element, set its text content with name of currently iterated account and append it to the <tr>.
    .append($('<td>').text(account.AccountStatus))
    .append ($('<select id="Accountchange"+r+ onchange="dropDownOnChange(this)"><option value="Valid">Valid</option><option value="Invalid">Invalid</option></select>'))

                    });
                }
        });

};
    var selectedValue;
    function dropDownOnChange(e){
    selectedValue=e.options[e.selectedIndex].value;
    alert("selectedValue:" + selectedValue);
}

---

您需要在函数中添加行dropDownOnChange@Priyank，我正在尝试在函数dropDownOnChange中添加行，但我不知道如何在更改下拉列表时获取AccountNumber。谢谢。您好，RubyI已经尝试了这个'var parent=$this.parentstr；alertparent+parent.val；'但上面写着undefined.@Priyank。谢谢你的帮助。我试图实现你的代码，但上面写着“Uncaught SyntaxError:意外标识符”。实际上，我需要从同一行中获取下拉值+AccountNo，而且我还可以获取多行。非常感谢你的帮助。//试试这个。previoud代码var currentRow=$e.closesttr中存在一些键入错误；var AccountNo=$td:eq0，$currentRow.text@普里扬克，非常感谢你。它起作用了。再次感谢。你好，鲁比

var currentRow= $(e).closest("tr");
var AccountNo= $("td:eq(0)",$(currentRow)).text();

//You can change the index eq(0) to eq(1) and so on to get the next cells. 
//Alternatively you can give an attribute to column while adding like 
//.append($('<td>').text(account.AccountNumber).attr("colType='AcNo'")) 
//And get Account No Like var AccountNo= $("td[colType='AcNo']",$(tr)).text();  
//Usign the alternative approch will make your code independent of index. which is good for //maintainability and readability