获取a中属性的值<;td>;用jQuery?
我有以下jQuery:获取a中属性的值<;td>;用jQuery?,jquery,Jquery,我有以下jQuery: $.fn.dataTableExt.afnSortData['dom-text'] = function (oSettings, iColumn) { var aData = []; $('td:eq(' + iColumn + ') input', oSettings.oApi._fnGetTrNodes(oSettings)).each(function () { aData.push(this.value); });
$.fn.dataTableExt.afnSortData['dom-text'] = function (oSettings, iColumn) {
var aData = [];
$('td:eq(' + iColumn + ') input', oSettings.oApi._fnGetTrNodes(oSettings)).each(function () {
aData.push(this.value);
});
return aData;
}
我用它来获取td元素中输入的值
但是,我的HTML现在看起来如下所示:
<td id="tempRowKey_117" class=" sorting_1" data-rk="100001">
<input type="text" value="10.0.1" id="TempRowKey_117">
</td>
如何更改jQuery,使其现在获得数据rk的值而不是输入值
换句话说,我想得到“10001”您是否尝试过将选择器更改为
$('td:eq('+iColumn+'))”
并将值作为aData.push($(this.data('rk'));
?
$.fn.dataTableExt.afnSortData['dom-text'] = function (oSettings, iColumn) {
var aData = [];
$('td:eq(' + iColumn + ')', oSettings.oApi._fnGetTrNodes(oSettings)).each(function () {
aData.push($(this).attr('data-rk'));
});
return aData;
}