Jquery HttpStatusCodeResult.StatusDescription的可靠性如何?
考虑以下控制器操作,其中有大量的例子在web上:Jquery HttpStatusCodeResult.StatusDescription的可靠性如何?,jquery,ios,angularjs,asp.net-mvc,asp.net-mvc-5,Jquery,Ios,Angularjs,Asp.net Mvc,Asp.net Mvc 5,考虑以下控制器操作,其中有大量的例子在web上: public ActionResult Fail() { return new HttpStatusCodeResult(HttpStatusCode.BadRequest, "My helpful message"); } 现在,我们将通过Ajax调用该操作,并在页面中显示结果 <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <
public ActionResult Fail()
{
return new HttpStatusCodeResult(HttpStatusCode.BadRequest, "My helpful message");
}
现在,我们将通过Ajax调用该操作,并在页面中显示结果
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script type="text/javascript">
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function () {
if (xmlhttp.readyState == 4) {
document.body.innerHTML = xmlhttp.response;
}
}
xmlhttp.open("POST", "/log/fail", true);
xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xmlhttp.send();
</script>
</head>
<body>
</body>
</html>
jQuery
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="https://code.jquery.com/jquery-2.1.4.min.js"></script>
<script type="text/javascript">
$.ajax({ url: '/log/fail', method:'POST' }).error(function (response) {
document.body.innerHTML = response.statusText; // 'Bad request' in iOS
});
</script>
</head>
<body>
</body>
</html>
$.ajax({url:'/log/fail',方法:'POST'})。错误(函数(响应){
document.body.innerHTML=response.statusText;///iOS中的“错误请求”
});
您可以依赖服务器返回的状态代码结果(至少在IIS上)
但是,不能保证浏览器将支持它
但是您的断言是正确的,即您应该使用模型返回任何错误以显示在客户端上,以获得一致的结果
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="https://code.jquery.com/jquery-2.1.4.min.js"></script>
<script type="text/javascript">
$.ajax({ url: '/log/fail', method:'POST' }).error(function (response) {
document.body.innerHTML = response.statusText; // 'Bad request' in iOS
});
</script>
</head>
<body>
</body>
</html>