Jquery 显示django ajax搜索的搜索结果_Jquery_Ajax_Django

Jquery 显示django ajax搜索的搜索结果

jquery ajax django

Jquery 显示django ajax搜索的搜索结果,jquery,ajax,django,Jquery,Ajax,Django,我一直在学习django ajax搜索教程。我无法在模板中显示结果，尽管它们在终端中“打印”得很好。如何在html页面上获得这些结果？以下是我的观点.py： def search_titles(request): if request.method == 'POST': search_text = request.POST['search_text'] print search_text search = UploadFile.objec

我一直在学习django ajax搜索教程。我无法在模板中显示结果，尽管它们在终端中“打印”得很好。如何在html页面上获得这些结果？ 以下是我的观点.py：

def search_titles(request):
    if request.method == 'POST':
        search_text = request.POST['search_text']
        print search_text
        search = UploadFile.objects.filter(event_name__icontains=search_text)
        for i in search:
            print(i.event_name)

        context={
        'search':search,
        }

        return render(request,'ajax_search.html',context)

HTML模板：

<!DOCTYPE html>
<html>
<head>
    <title>Search</title>

    <script type="text/javascript" src="http://code.jquery.com/jquery-2.0.0.min.js"></script>
    <script type="text/javascript" src="/static/assets/js/ajax.js"></script>
</head>
<body>
<h3>Search</h3>
                {% csrf_token %}
                <input type ='text' id="search" name="search"/>
                <ul id="search-results">

                </ul>



</body>
</html>

ajax_search.html：

{% if search.count>0 %}

{% for i in search %}

<li><a href="events/{{i.event_name}}">{{i.event_name}}</a></li>
{% endfor %}

{% else %}
<li>Nothing Found :(</li>

{% endif %}

线程似乎也有类似的问题。但接下来的操作甚至不会在终端中给出搜索结果。

您应该使用HttpResponse返回对ajax请求的响应。如果您使用的是Django 1.7+，那么使用JsonResponse

from django.template.loader import render_to_string
from django.http import HttpResponse

def search_titles(request):
    context ={}
    if request.method == 'POST':
        search_text = request.POST['search_text']
        search = UploadFile.objects.filter(
                     event_name__icontains=search_text)   
        context={
        'search':search,
        }
        html = render_to_string('search_results.html',context)

        return HttpResponse(html, content_type="application/json")    
    return render(request,'ajax_search.html',context)

创建一个新的html

search_results.html：

{% for i in search %}<li>{{i.event_name}}</li>{% endfor %}

{%fori in search%}{{i.event_name}{%endfor%}

你能解释一下如何更新seachSuccess函数吗……这一直是我的问题……我对ajaxI更新的代码了解不多。因此，搜索成功不需要改变

from django.template.loader import render_to_string
from django.http import HttpResponse

def search_titles(request):
    context ={}
    if request.method == 'POST':
        search_text = request.POST['search_text']
        search = UploadFile.objects.filter(
                     event_name__icontains=search_text)   
        context={
        'search':search,
        }
        html = render_to_string('search_results.html',context)

        return HttpResponse(html, content_type="application/json")    
    return render(request,'ajax_search.html',context)

{% for i in search %}<li>{{i.event_name}}</li>{% endfor %}