Warning: file_get_contents(/data/phpspider/zhask/data//catemap/5/date/2.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Jquery 在twitter引导中创建两个下拉菜单_Jquery_Css_Twitter Bootstrap - Fatal编程技术网

Jquery 在twitter引导中创建两个下拉菜单

Jquery 在twitter引导中创建两个下拉菜单,jquery,css,twitter-bootstrap,Jquery,Css,Twitter Bootstrap,我正试图创建一个项目列表,其中两个项目是借助twitter引导的下拉菜单。 这是我的尝试代码: <div class="row"> <ul class="nav nav-tabs"> <li class="active span2">1</li> <li class="span2">2</li> <li class="span2"> <

我正试图创建一个项目列表,其中两个项目是借助twitter引导的下拉菜单。 这是我的尝试代码:

<div class="row">
    <ul class="nav nav-tabs">
        <li class="active span2">1</li>
        <li class="span2">2</li>
        <li class="span2">
        <div class="dropdown">
        <button class="btn dropdown-toggle sr-only" type="button" id="dropdownMenu1" data-toggle="dropdown">
        3(Dropdown)
        <span class="caret"></span>
      </button>
      <ul class="dropdown-menu" role="menu" aria-labelledby="dropdownMenu1">
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">1</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">2</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">3</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">4</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">5</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">6</a></li>
      </ul>
    </div>
        </li>
        <li class="span2">4</li>
        <li class="span2">
        <button class="btn dropdown-toggle sr-only" type="button" id="dropdownMenu2" data-toggle="dropdown">
        5(dropdown)
        <span class="caret"></span>
        </button>
        <ul class="dropdown-menu" role="menu" aria-labelledby="dropdownMenu2">
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">1</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">2</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">3</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">4</a></li>
        </ul>
        </li>
    </ul>
</div>

  • 1
  • 2
  • 3(下拉列表)
  • 4
  • 5(下拉列表)

但当我尝试时,第一个下拉菜单很好,但另一个不会在单击时下拉。谁能解释一下原因吗?

您错过的第二个下拉列表必须用
包装。

试试这个

<div class="row">
    <ul class="nav nav-tabs">
        <li class="active span2">1</li>
        <li class="span2">2</li>
        <li class="span2">
        <div class="dropdown">
        <button class="btn dropdown-toggle sr-only" type="button" id="dropdownMenu1" data-toggle="dropdown">
        3(Dropdown)
        <span class="caret"></span>
      </button>
      <ul class="dropdown-menu" role="menu" aria-labelledby="dropdownMenu1">
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">1</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">2</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">3</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">4</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">5</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">6</a></li>
      </ul>
    </div>
        </li>
        <li class="span2">4</li>
        <li class="span2">
        <div class="dropdown">
            <button class="btn dropdown-toggle sr-only" type="button" id="dropdownMenu2" data-toggle="dropdown">
        5(dropdown)
        <span class="caret"></span>
        </button>
        <ul class="dropdown-menu" role="menu" aria-labelledby="dropdownMenu2">
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">1</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">2</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">3</a></li>
        <li role="presentation"><a role="menuitem" tabindex="-1" href="#">4</a></li>
        </ul>
        </div>
        </li>
    </ul>
</div>

  • 1
  • 2
  • 3(下拉列表)
  • 4
  • 5(下拉列表)