用swift 3解析json不适合我

几天来，我一直试图从下面的json文件中获取“名称”，但没有成功。谁能给我指一下正确的方向吗？我已成功访问结果数组，但没有访问“name”变量

{
    "count": 7,
    "next": null,
    "previous": null,
    "results": [
    {
    "id": 10,
    "name": "Abs"
    },
    {
    "id": 8,
    "name": "Arms"
    },
    {
    "id": 12,
    "name": "Back"
    },
    {
    "id": 14,
    "name": "Calves"
    },
    {
    "id": 11,
    "name": "Chest"
    },
    {
    "id": 9,
    "name": "Legs"
    },
    {
    "id": 13,
    "name": "Shoulders"
    }
    ]
}

我的代码是这样的

    let url = URL(string: "https://wger.de/api/v2/exercisecategory")!

    let task = URLSession.shared.dataTask(with: url) { (data, response, error) in
        if error != nil {
            print(error!)
        } else {
            if let content = data {

                do {
                    let json = try? JSONSerialization.jsonObject(with: content, options:[]) {
                        if let content = json as? [String: Any] {
                            if let results = content["results"] as? [Any] {
                                for result in results {
                                    if let bodypart = result["name"] as! [String: Any] {
                                        print(bodypart)
                                    }
                                }
                            }
                        }
                    }
                }
            }
        }
    }

---

问题是您正在将

name

强制转换为

Dictionary

，但这只是

String

而已，您还需要将

结果强制转换为Dictionary的数组，而不是
Any的数组。所以整个代码都是这样的

if let json = try? JSONSerialization.jsonObject(with: content, options:[]), 
   let content = json as? [String: Any], 
   let results = content["results"] as? [[String:Any]] {
      for result in results {
          if let bodypart = result["name"] as? String {
              print(bodypart)
          }
      }
}

@Niklas欢迎伙伴：）