REST服务| JSON响应格式

我使用JAX-RS的RESTEasy实现创建了一个RESTWeb服务。我有一个Employee POJO类，它作为响应发送。响应是json格式的。问题是我正在将员工名单返回给打电话的人。下面是代码

下面是Employee POJO类

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
"employeeId",
"name",
"role"
})
@XmlRootElement(name = "employee")
public class Employee {

@XmlElement(required = true)
protected String employeeId;
@XmlElement(required = true)
protected Name name;
@XmlElement(required = true)
protected String role;

/**
 * Gets the value of the employeeId property.
 * 
 * @return
 *     possible object is
 *     {@link String }
 *     
 */
public String getEmployeeId() {
    return employeeId;
}

/**
 * Sets the value of the employeeId property.
 * 
 * @param value
 *     allowed object is
 *     {@link String }
 *     
 */
public void setEmployeeId(String value) {
    this.employeeId = value;
}

/**
 * Gets the value of the name property.
 * 
 * @return
 *     possible object is
 *     {@link Name }
 *     
 */
public Name getName() {
    return name;
}

/**
 * Sets the value of the name property.
 * 
 * @param value
 *     allowed object is
 *     {@link Name }
 *     
 */
public void setName(Name value) {
    this.name = value;
}

/**
 * Gets the value of the role property.
 * 
 * @return
 *     possible object is
 *     {@link String }
 *     
 */
public String getRole() {
    return role;
}

/**
 * Sets the value of the role property.
 * 
 * @param value
 *     allowed object is
 *     {@link String }
 *     
 */
public void setRole(String value) {
    this.role = value;
}

}

下面是发送响应的服务方法

@GET
@Path("/json/employees/")
@Produces("application/json")
public List<Employee> listEmployeesJSON() {
    return new ArrayList<Employee>(employees.values());

但是，我希望格式如下：

{
"employee": [{
    "employeeId": 876,
    "name": {
        "salutation": "Mr.",
        "firstName": "Manav",
        "lastName": "Bhanot"
    },
    "role": "Senior Engineer"
},{
    "employeeId": 923,
    "name": {
        "salutation": "Mr.",
        "firstName": "Saumya",
        "lastName": "Mittal"
    },
    "role": "Senior Engineer"
}]
}

---

如何实现这一点？

您可以通过使用包装器类来实现这一点。一个简单的例子是：

public class EmployeeWrapper {
    private final ArrayList<Employee> employees;

    @JsonCreator
    public EmployeeWrapper(@JsonProperty("employees") ArrayList<Employee> employees) {
        this.employees = employees;
    }

    public ArrayList<Employee> getEmployees() {
        return employees;
    }
}

公共类EmployeeWrapper{
私人最终ArrayList员工；
@JsonCreator
公共EmployeeWrapper（@JsonProperty（“employees”）ArrayList employees）{
这是。雇员=雇员；
}
公共阵列列表getEmployees（）{
返回员工；
}
}

---

在响应中返回包装器对象，而不是普通的

ArrayList

它会给我以下输出[{“employeeId”：“2”，“employeeName”：“Justin”，“job”：“Business Analyst”}，{“employeeId”：“1”，“employeeName”：“Fabrizio”，“job”：“Software Engineer”}Ok。如果输出有问题，你能更具体一点吗？嗨，山姆，输出接近我想要的。输出中没有外部对象employee:。我已将服务方法返回类型修改为：returnnewEmployeeWrapper（newArrayList（employees.values（））.getEmployee（）；我不确定我是否正确使用了你的解决方案。我现在正在想办法。我还有一个问题。这是可以推广的，还是我必须为每个发送arraylist作为响应的情况创建一个包装器？

public class EmployeeWrapper {
    private final ArrayList<Employee> employees;

    @JsonCreator
    public EmployeeWrapper(@JsonProperty("employees") ArrayList<Employee> employees) {
        this.employees = employees;
    }

    public ArrayList<Employee> getEmployees() {
        return employees;
    }
}