如何使用serializer（Symfony 4）以正确的格式创建json字符串？

我正在使用序列化程序创建json字符串：

$table = $this->getDoctrine()->getRepository(Article::class)->findAll();

$serializer = new Serializer(array(new GetSetMethodNormalizer()), array('json' => new JsonEncoder()));
$json_string = $serializer->serialize($table, 'json');

$table的结果是：

array(2) { [0]=> object(App\Entity\Article)#5975 (3) { ["id":"App\Entity\Article":private]=> int(1) ["title":"App\Entity\Article":private]=> string(9) "Article 1" ["body":"App\Entity\Article":private]=> string(32) "This is the body for article one" } [1]=> object(App\Entity\Article)#5979 (3) { ["id":"App\Entity\Article":private]=> int(2) ["title":"App\Entity\Article":private]=> string(11) "Article Two" ["body":"App\Entity\Article":private]=> string(32) "This is the body for article two" } } 

这是$json_字符串的结果：

string(145) "[{"id":1,"title":"Article 1","body":"This is the body for article one"},{"id":2,"title":"Article Two","body":"This is the body for article two"}]" 

但这不是我需要的正确格式。我需要这样编码：

{
  "recordsTotal": 10,
  "recordsFiltered": 10,
  "draw": 1,
  "data": [
    [
      "Airi",
      "Satou",
      "Accountant",
      "Tokyo",
      "28th Nov 08",
      "$162,700"
    ],
    [
      "Angelica",
      "Ramos",
      "Chief Executive Officer (CEO)",
      "London",
      "9th Oct 09",
      "$1,200,000"
    ],
    [
      "Ashton",
      "Cox",
      "Junior Technical Author",
      "San Francisco",
      "12th Jan 09",
      "$86,000"
    ],
    [
      "Bradley",
      "Greer",
      "Software Engineer",
      "London",
      "13th Oct 12",
      "$132,000"
    ],
    [
      "Brenden",
      "Wagner",
      "Software Engineer",
      "San Francisco",
      "7th Jun 11",
      "$206,850"
    ],
    [
      "Brielle",
      "Williamson",
      "Integration Specialist",
      "New York",
      "2nd Dec 12",
      "$372,000"
    ],
    [
      "Bruno",
      "Nash",
      "Software Engineer",
      "London",
      "3rd May 11",
      "$163,500"
    ],
    [
      "Caesar",
      "Vance",
      "Pre-Sales Support",
      "New York",
      "12th Dec 11",
      "$106,450"
    ],
    [
      "Cara",
      "Stevens",
      "Sales Assistant",
      "New York",
      "6th Dec 11",
      "$145,600"
    ],
    [
      "Cedric",
      "Kelly",
      "Senior Javascript Developer",
      "Edinburgh",
      "29th Mar 12",
      "$433,060"
    ]
  ]
}

带标准化器的Aproach：

$normalizer = new ObjectNormalizer();
$encoder = new JsonEncoder();
$serializer = new Serializer(array($normalizer), array($encoder));
$json_string = $serializer->serialize($table, 'json');

结果:

string(145) "[{"id":1,"title":"Article 1","body":"This is the body for article one"},{"id":2,"title":"Article Two","body":"This is the body for article two"}]" 

---

您可以通过

JsonSerializable

界面来控制这一点

class Article implements JsonSerializable {
public function jsonSerialize() {
        $arr = [
            $this->firstName,
            $this->secondName,
            //...
            ];
        return $arr;
    }
}

---

您可以通过

JsonSerializable

界面来控制这一点

class Article implements JsonSerializable {
public function jsonSerialize() {
        $arr = [
            $this->firstName,
            $this->secondName,
            //...
            ];
        return $arr;
    }
}

---

面对同样的问题，找到了以下解决方案：

    $array = json_decode($serializer->serialize($object, 'json'), true);
    $entryJSONFile = json_encode($array, JSON_PRETTY_PRINT);

---

这确实起到了作用，但我仍然不习惯双重转换。

面对同样的问题，我找到了以下解决方案：

    $array = json_decode($serializer->serialize($object, 'json'), true);
    $entryJSONFile = json_encode($array, JSON_PRETTY_PRINT);

---

这确实起到了作用，但我仍然不习惯双重转换。

我知道这是从2018年开始的。但我需要给出这个解决方案，经过几个小时的研究，我发现：

$response = new Response($serializer->serialize($data, JsonEncoder::FORMAT, [JsonEncode::OPTIONS => JSON_UNESCAPED_UNICODE | JSON_PRETTY_PRINT]));
$response->headers->set('Content-Type', 'application/json');
return $response;

---

在Symfony 4.2中对我来说效果非常好，我知道这是从2018年开始的。但我需要给出这个解决方案，经过几个小时的研究，我发现：

$response = new Response($serializer->serialize($data, JsonEncoder::FORMAT, [JsonEncode::OPTIONS => JSON_UNESCAPED_UNICODE | JSON_PRETTY_PRINT]));
$response->headers->set('Content-Type', 'application/json');
return $response;

---

在Symfony 4.2中，我的工作非常好。

尝试将

$table

封装到一个包含键的数组中

recordsTotal、recordsFiltered、draw、data

、parse

$table

，并获得所需的数据。@AlexandrePainchaud不能直接创建一个包含键的数组吗？在这种情况下，我不确定。你只需要不带任何键的数据..用PHP实现这一点并不困难。我给你发了一个例子，说明每个属性的前缀都是

org\uuu

。所以你可以直接返回

'

。编辑规范化程序的目标是自定义键值尝试，以将

$table

封装到一个包含键的数组中

recordsTotal、recordsFiltered、draw、data

、parse

$table

，并获取所需的数据。@AlexandrePainchaud无法直接创建一个包含键的数组？在这种情况下，我不确定。你只需要不带任何键的数据..用PHP实现这一点并不困难。我给你发了一个例子，说明每个属性的前缀都是

org\uuu

。所以你可以直接返回

'

。EditNormalizer的目标是自定义键实际上，您可以仅使用Normalizer避免双重转换：$array=$Normalizer->normalize（$object）$entryJSONFile=json\u encode（$array，json\u PRETTY\u PRINT）；实际上，只使用normalizer可以避免双重转换：$array=$normalizer->normalize（$object）$entryJSONFile=json\u encode（$array，json\u PRETTY\u PRINT）；