XML转换为JSON R
在将XML转换为JSON时,R中的包似乎不能正常工作。我用“XML”包尝试了RJSONIO、rjson和jsonlite。我首先解析XML并使用XML::xmlToList()将其转换为列表,然后使用这3个包中的toJSON()将其转换为JSON 我的XML文件:XML转换为JSON R,json,r,xml,Json,R,Xml,在将XML转换为JSON时,R中的包似乎不能正常工作。我用“XML”包尝试了RJSONIO、rjson和jsonlite。我首先解析XML并使用XML::xmlToList()将其转换为列表,然后使用这3个包中的toJSON()将其转换为JSON 我的XML文件: <?xml version="1.0" encoding="utf-8"?> <votes> <row Id="1" PostId="1" VoteTypeId="2" CreationDate="2
<?xml version="1.0" encoding="utf-8"?>
<votes>
<row Id="1" PostId="1" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
<row Id="2" PostId="1" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
<row Id="3" PostId="3" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
</votes>
这显然是错误的,因为重复的字段名
从jsonlite转换的JSON文件:
{"row":["1","1","2","2014-05-13T00:00:00.000"],
"row.1":["2","1","2","2014-05-13T00:00:00.000"],
"row.2":["3","3","2","2014-05-13T00:00:00.000"]}
这很奇怪,因为子文档数组中应该只有一个字段名“row”,而不是递增的“rows”数组。它甚至没有字段名
从rjson转换的JSON文件:
{
"row": {
"Id": "1",
"PostId": "1",
"VoteTypeId": "2",
"CreationDate": "2014-05-13T00:00:00.000"
},
"row": {
"Id": "2",
"PostId": "1",
"VoteTypeId": "2",
"CreationDate": "2014-05-13T00:00:00.000"
}
}
理想的JSON文件如下所示:
{"votes" : {
"row" : [
{
"Id" : "1",
"PostId" : "1",
"VoteTypeId" : "2",
"CreationDate" : "2014-05-13T00:00:00.000"
},
{
"Id" : "2",
"PostId" : "1",
"VoteTypeId" : "2",
"CreationDate" : "2014-05-13T00:00:00.000"
}
]
}
}
寻找解决方案。非常感谢您的帮助。
xml2
和jsonlite
为您提供了大部分帮助,但您甚至没有向我们展示您知道的R code,更不用说真正尝试了解决方案,因此这里发布了一个部分解决方案,它可以帮助其他人:
library(xml2)
library(jsonlite)
read_xml('<?xml version="1.0" encoding="utf-8"?>
<votes>
<row Id="1" PostId="1" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
<row Id="2" PostId="1" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
<row Id="3" PostId="3" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
</votes>') -> doc
x <- xml2::as_list(doc)
xl <- lapply(x, attributes)
toJSON(xl, pretty = TRUE, auto_unbox = TRUE)
## {
## "row": {
## "Id": "1",
## "PostId": "1",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## },
## "row.1": {
## "Id": "2",
## "PostId": "1",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## },
## "row.2": {
## "Id": "3",
## "PostId": "3",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## }
## }
显示用于获取错误JSON字符串的代码以及XML转换产生的数据,以便我们可以帮助您正确地解决问题。感谢@hrbrmstr的回答。正如我在文章中所说,我已经尝试过jsonlite,但输出并不理想,正如您在这里看到的,理想的输出是一个字段名“row”,其中包含子文档数组,而不是单个文档中的多个递增“row”。
{"votes" : {
"row" : [
{
"Id" : "1",
"PostId" : "1",
"VoteTypeId" : "2",
"CreationDate" : "2014-05-13T00:00:00.000"
},
{
"Id" : "2",
"PostId" : "1",
"VoteTypeId" : "2",
"CreationDate" : "2014-05-13T00:00:00.000"
}
]
}
}
library(xml2)
library(jsonlite)
read_xml('<?xml version="1.0" encoding="utf-8"?>
<votes>
<row Id="1" PostId="1" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
<row Id="2" PostId="1" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
<row Id="3" PostId="3" VoteTypeId="2" CreationDate="2014-05-13T00:00:00.000" />
</votes>') -> doc
x <- xml2::as_list(doc)
xl <- lapply(x, attributes)
toJSON(xl, pretty = TRUE, auto_unbox = TRUE)
## {
## "row": {
## "Id": "1",
## "PostId": "1",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## },
## "row.1": {
## "Id": "2",
## "PostId": "1",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## },
## "row.2": {
## "Id": "3",
## "PostId": "3",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## }
## }
xml_find_all(doc, "//votes/row") %>%
map_chr(~{
toJSON(as.list(xml_attrs(.x)), auto_unbox = TRUE, pretty = TRUE)
}) %>%
paste0(collapse=",\n") %>%
gsub("[\n]", "\n ", .) %>%
sprintf('{ "votes" : {\n row" : [\n %s]\n }\n}', .) %>%
cat()
## { "votes" : {
## row" : [
## {
## "Id": "1",
## "PostId": "1",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## },
## {
## "Id": "2",
## "PostId": "1",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## },
## {
## "Id": "3",
## "PostId": "3",
## "VoteTypeId": "2",
## "CreationDate": "2014-05-13T00:00:00.000"
## }]
## }
## }