如何在join laravel上使用不同的ID从同一个表中检索不同的名称

我需要从destinations表中获取每个from_destination_id和to_destination_id的名称 从DestinationName到toDestinationName

$bookingTransfersData = DB::table('transfers as t')
            ->select('t.periodStart as periodStart', 't.periodEnd as periodEnd','t.days','t.transfer_id','t.cost_round_trip',
                't.cost_one_way','t.status','d.destination_id as destinationId','d.name as destinationName', 't.type',
                'tf.name as officeName', 'ag.name as agencyName', 'u.name as userName', 'v.name as vehicleName')
            ->join('destinations as d', function ($join){
                $join->on('t.from_destination_id','=','d.destination_id')
                    ->orOn('t.to_destination_id','=','d.destination_id');
            })->join('vehicles as v','t.vehicle_id','=','v.vehicle_id')
            ->join('transfer_offices as tf','t.office_id','=','tf.transfer_office_id')
            ->join('agencies as ag','t.forAgency_id','=','ag.agency_id')
            ->join('users as u','t.addedBy_user_id','=','u.id')
            ->get();

我想在这个结果之后得到每个id的名称

$searchResults = $bookingTransfersData
            ->where('periodStart','between', $periodStart && $periodEnd)
            ->where('periodEnd','between', $periodStart && $periodEnd)
            ->where('destinationName','=',$from_destination_name && $to_destination_name)->where('type','like', $type);

比如：

$fromDestinationName = $searchResults->pluck('from_destination_id','destinationName')
            ->where('from_destination_id','=','destinationId');

但是

$fromDestinationName

返回一个空集合

---

请帮助：）

我通过删除此连接解决了此问题：

->join('destinations as d', function ($join){
                $join->on('t.from_destination_id','=','d.destination_id')
                    ->orOn('t.to_destination_id','=','d.destination_id');
            })

并为每个目的地添加一个联接以检索每个名称 如果我不将两次加入的表名添加为，将其命名为新名称，那么这将不起作用

“目的地为d1”

和

“目的地为d2”

$bookingTransfersData = DB::table('transfers as t')
            ->select('t.periodStart as periodStart', 't.periodEnd as periodEnd','t.days','t.transfer_id','t.cost_round_trip',
                't.cost_one_way','t.status','d1.destination_id as fromDestinationId','d1.name as fromDestinationName', 't.type',
                't.to_destination_id','tf.name as officeName', 'ag.name as agencyName', 'u.name as userName', 'v.name as vehicleName',
                't.from_destination_id', 'd2.destination_id as toDestinationId','d2.name as toDestinationName')
            ->join('destinations as d1','t.from_destination_id','=','d1.destination_id')
            ->join('destinations as d2','t.to_destination_id','=','d2.destination_id')
            ->join('vehicles as v','t.vehicle_id','=','v.vehicle_id')
            ->join('transfer_offices as tf','t.office_id','=','tf.transfer_office_id')
            ->join('agencies as ag','t.forAgency_id','=','ag.agency_id')
            ->join('users as u','t.addedBy_user_id','=','u.id')->get();

问题解决了：）