Linux 如何计算所服务http请求的质量
我有一个shell脚本,它以百分比计算tps、平均响应时间和响应时间质量。但我认为质量响应公式不正确,请建议如何以95%的百分比计算响应时间的质量Linux 如何计算所服务http请求的质量,linux,apache,shell,httprequest,Linux,Apache,Shell,Httprequest,我有一个shell脚本,它以百分比计算tps、平均响应时间和响应时间质量。但我认为质量响应公式不正确,请建议如何以95%的百分比计算响应时间的质量 calculation () { echo "starting calculation of the data in the files:" if [ -f "/tmp/log/tps_access/access$today_date.log" ] then total_request=$( cat /tmp/log/tps_access/
calculation () {
echo "starting calculation of the data in the files:"
if [ -f "/tmp/log/tps_access/access$today_date.log" ]
then
total_request=$( cat /tmp/log/tps_access/access$today_date.log | wc -l )
total_500E_request=$( cat /tmp/log/tps_access/access$today_date.log | awk -F"\"" '{ print $3}' | awk -F" " '{ print $1}' | grep "^5[0-9][0-9]$" | wc -l)
average_response_time=$( cat /tmp/log/tps_access/access$today_date.log | awk -F"\"" '{ print $9}' | awk '{sum+=$1; ++n} END { rounded = sprintf("%.2f", sum/n ); print rounded }')
percentile=$( cut /tmp/log/tps_access/access$today_date.log -d '"' -f9 |sort -n| awk 'BEGIN{c=0} {total[c]=$1; c++;} END{ rounded = sprintf("%.2f", total[int((NR*0.95)-1)] ); print rounded } ' )
head_time=$( head /tmp/log/tps_access/access$today_date.log | awk -F" " '{ print $4 }' | awk -F"[" '{ print $2 }' | awk -F"/" '{ print $1"-"$2"-"$3}' | awk -F":" '{ print $1" "$2":"$3":"$4}' | head -1 )
tail_time=$( tail /tmp/log/tps_access/access$today_date.log | awk -F" " '{ print $4 }' | awk -F"[" '{ print $2 }' | awk -F"/" '{ print $1"-"$2"-"$3}' | awk -F":" '{ print $1" "$2":"$3":"$4}' | tail -1 )
sec_old=$(date -d "$head_time" +%s)
sec_new=$(date -d "$tail_time" +%s)
DIFF=$(( (sec_new - sec_old) ))
tps=$(echo "scale=2; $total_request/$DIFF * 1" | bc )
request_servered_in_defined_sec=$( echo "scale=2; $total_request/$DIFF * $second" | bc )
sum=$(cat /tmp/log/tps_access/access$today_date.log | awk -F"\"" '{ print $9}' | awk '{sum+=$1; ++n} END { print sum }')
quality_per_sec=$( echo "scale=5; $sum/$total_request * $second" | bc )
quality_score=$( echo "scale=5; $quality_per_sec/$sum * 100" | bc )
if [ $total_500E_request -gt $threshold ]
then
echo "Count of 500 error request increases so sending mail to the team:"
send_mail error
else
echo "Writing all the stats in a file and wait for the next run:"
send_mail all
exit
fi
fi
}
正确功能
算计{
echo开始计算文件中的数据:
if[-f/tmp/log/tps\u access/access$today\u date.log]
然后
请求总数=$cat/tmp/log/tps\u访问/访问$today\u date.log | wc-l
请求总数=$cat tmp/log/tps_访问/访问$today_date.log | awk-F\{print$3}'| awk-F{print$1}'| grep^5[0-9][0-9]$| wc-l
百分比_500E=$printf%.2f$echo scale=5;$total_500E_request/$total_request*100 | bc
平均响应时间=$cat/tmp/log/tps\u访问/访问$today\u date.log | awk-F\{print$9}'| awk'{sum+=1;++n}END{rounded=sprintf%.2f,sum/n;print rounded}
百分位数=$TUT/TMP/Log/TPSYAccess/Access $TayayAddia.log′-''-f9排序-n'AWK ''开始{C=0 }{{总数〕[C]=1;C++;} {{rnn==SaveTf%.2f,全部[tnnr*0.95-1;打印圆} ]
head_time=$head/tmp/log/tps_access/access$today_date.log | awk-F{print$4}| awk-F[{print$2}| awk-F/{print$1-$2-$3}| awk-F:{print$1$2:$3:$4}| head 1-1
tail_time=$tail/tmp/log/tps_access/access$today_date.log | awk-F{print$4}| awk-F[{print$2}| awk-F/{print$1-$2-$3}| awk-F:{print$1$2:$3:$4}| tail-1
秒旧=$date-d$head\u时间+%s
sec_new=$date-d$tail_time+%s
差异=$sec_新-sec_旧
tps=$echo scale=2;$total_request/$DIFF*1|bc
已定义的请求中的已服务请求秒=$echo scale=2;$total请求/$DIFF*$second | bc
质量每秒=$awk-F \-v val=$second'$NF}我认为这是我使用的一个遗留代码,作为标准,我首先使用fluentd将日志发送到logmatic,在logmatic中,计算百分位数和所有内容都非常简单
这不是正确的方法。下面是正确的方法