Lua：如何将大量数字转换为1个变量

不能在一个变量中存储多个值

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您可以在一个表中存储多个值，然后将单个表放在变量中，或者如果您希望在一个位置存储多个表，则可以将多个值放在另一个表中。

您可以使用数字for循环。为了在一个变量中存储多个值，请使用表

    lives=1


while lives > 0 do

math.randomseed(os.time())
local randomNumber1 = math.random(7200)
local randomNumber = math.random(randomNumber1, 7200)


print("Welcome to roulette!")




local a= >3500
local b= 
local c= <3700

local number1 = io.read()
local number1 = tonumber(number1)

if
    number1== a
    and randomNumber == a then
    print("You won!")
    print("Number was "..randomNumber..)

else if
    number1 == b
    and randomNumber == b then
    print("You won!")
    print("Number was "..randomNumber..)

else if
    number1 == c
    and randomNumber == c then
    print("You won!")
    print("Number was "..randomNumber..)

else
    print("Du tabte")
    print("Number was "..randomNumber..)

io.read()


lives=lives-1

end

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我该怎么做？我是否需要制作一个包含3500个数字的巨大表格？你应该做一个Lua初学者教程。这是非常基本的Lua。看，我现在已经把我的整个脚本都放进去了。你的代码没有太多意义，而且充满了语法错误。你们应该解释一下你们想要实现什么。我正在尝试制作一个轮盘赌系统，稍后我可以把它放到游戏中，在GTA的一个名为FiveMyes的mod中，你们已经说过了。但是number1==b应该做什么呢，假设您希望b存储200个数字。是否要检查您的号码是否在该间隔内？

    lives=1


while lives > 0 do

math.randomseed(os.time())
local randomNumber1 = math.random(7200)
local randomNumber = math.random(randomNumber1, 7200)


print("Welcome to roulette!")




local a= >3500
local b= 
local c= <3700

local number1 = io.read()
local number1 = tonumber(number1)

if
    number1== a
    and randomNumber == a then
    print("You won!")
    print("Number was "..randomNumber..)

else if
    number1 == b
    and randomNumber == b then
    print("You won!")
    print("Number was "..randomNumber..)

else if
    number1 == c
    and randomNumber == c then
    print("You won!")
    print("Number was "..randomNumber..)

else
    print("Du tabte")
    print("Number was "..randomNumber..)

io.read()


lives=lives-1

end

local numbers = {}
local from = 3500
local to = 3699
for number = from, to do
  table.insert(numbers, number)
end