在Lua中更改表中的值
我试图创建一个表,并希望更改该表中特定键的值。问题是当我换钥匙时,所有的钥匙都会变在Lua中更改表中的值,lua,key,Lua,Key,我试图创建一个表,并希望更改该表中特定键的值。问题是当我换钥匙时,所有的钥匙都会变 function dump(o, nb) if nb == nil then nb = 0 end if type(o) == 'table' then local s = '' for i = 1, nb + 1, 1 do s = s .. " " end s = '{\n' for k,v in pair
function dump(o, nb)
if nb == nil then
nb = 0
end
if type(o) == 'table' then
local s = ''
for i = 1, nb + 1, 1 do
s = s .. " "
end
s = '{\n'
for k,v in pairs(o) do
if type(k) ~= 'number' then k = '"'..k..'"' end
for i = 1, nb, 1 do
s = s .. " "
end
s = s .. '['..k..'] = ' .. dump(v, nb + 1) .. ',\n'
end
for i = 1, nb, 1 do
s = s .. " "
end
return s .. '}'
else
return tostring(o)
end
end
Config={}
PlayersStatusTable={}
Config.DefaultStatus = {
hunger = 1000000,
thirst = 1000000,
}
local timeNow = os.clock()
PlayersStatusTable[12] = Config.DefaultStatus
PlayersStatusTable[112] = Config.DefaultStatus
PlayersStatusTable[54] = Config.DefaultStatus
for playerId, details in pairs(PlayersStatusTable) do
print("playerid1",playerId)
print(dump(PlayersStatusTable))
print(dump(PlayersStatusTable[112]))
print(dump(PlayersStatusTable[112].hunger))
PlayersStatusTable[112].hunger = 5
end
输出如下:
playerid1 112
{
[112] = {
["thirst"] = 1000000,
["hunger"] = 1000000,
},
[54] = {
["thirst"] = 1000000,
["hunger"] = 1000000,
},
[12] = {
["thirst"] = 1000000,
["hunger"] = 1000000,
},
}
{
["thirst"] = 1000000,
["hunger"] = 1000000,
}
1000000
playerid1 54
{
[112] = {
["thirst"] = 1000000,
["hunger"] = 5,
},
[54] = {
["thirst"] = 1000000,
["hunger"] = 5,
},
[12] = {
["thirst"] = 1000000,
["hunger"] = 5,
},
}
{
["thirst"] = 1000000,
["hunger"] = 5,
}
5
playerid1 12
{
[112] = {
["thirst"] = 1000000,
["hunger"] = 5,
},
[54] = {
["thirst"] = 1000000,
["hunger"] = 5,
},
[12] = {
["thirst"] = 1000000,
["hunger"] = 5,
},
}
{
["thirst"] = 1000000,
["hunger"] = 5,
}
5
我只希望id 112的饥饿度为5。您将同一个表分配给所有3个键,因此它们都指向正在更改的同一个表。您需要确保在分配给每个键时创建一个新表
local function shallowCopy(t)
local result = {}
for k, v in pairs(t) do
result[k] = v
end
return result
end
PlayersStatusTable[12] = shallowCopy(Config.DefaultStatus)
您将同一个表分配给所有3个键,因此它们都指向正在更改的同一个表。您需要确保在分配给每个键时创建一个新表
local function shallowCopy(t)
local result = {}
for k, v in pairs(t) do
result[k] = v
end
return result
end
PlayersStatusTable[12] = shallowCopy(Config.DefaultStatus)
哦,好吧,现在我明白了,我想这和引用/值类型有关吧?我会试试你的解决方案哦,好吧,现在我明白了,我想这和引用/值类型有关吧?我会试试你的解决办法