Lua 如何延迟gotoscene

每当特定食物击中猴子时，游戏就会重新启动，但我想延迟几秒钟，并在重新启动前显示一些文字，但我似乎不能。不拖延,

 local function monkeyCollision( self, event )
    if event.phase == "began" then
        if event.target.type == "monkey" and event.other.type == "food" then

            print( "chomp!" )
            event.other.alpha = 0
            event.other:removeSelf() 
            addToScore(5)
            -- get points!
        else
            print("ow!")
            monkey.alpha = 0
            monkey:removeSelf()
            displayScore = display.newText( "The total score is " .. score , 0, 0, "Helvetica", 30 )
             displayScore.x = screenLeft +150
            displayScore.y = screenRight-100
            displayre = display.newText( "  The game is going restart", 0, 0, "Helvetica", 25 )
    displayre.x = screenLeft +150
            displayre.y = screenRight-200
           storyboard.gotoScene("play", "fade", 1000) 
           end

---

为什么不把它放在计时器里呢

timer.performWithDelay(5000, function() storyboard.gotoScene("play", "fade", 1000); end)

---

在调用storybaord.gotoScene（）之前会延迟5秒，为什么不将其放入计时器中：

timer.performWithDelay(5000, function() storyboard.gotoScene("play", "fade", 1000); end)

---

这将在调用storybaord.gotoScene（）之前延迟5秒。

根据Rob的喜好添加计时器

timer.performWithDelay(5000, function() storyboard.gotoScene("play", "fade", 1000); end)

但你现在也有问题了。如果你已经吃了另一种食物，又吃了另一种呢？这将使多个计时器关闭，并可能出现故障，因为它将删除已删除的猴子

local lostGame = false

local function monkeyCollision( self, event )
    if event.phase == "began" then
        if event.target.type == "monkey" and event.other.type == "food" then

            print( "chomp!" )
            event.other.alpha = 0
            event.other:removeSelf() 
            addToScore(5)
            -- get points!
        else

            if lostGame == false then
                print("ow!")
                monkey.alpha = 0
                monkey:removeSelf()
                displayScore = display.newText( "The total score is " .. score , 0, 0, "Helvetica", 30 )
                displayScore.x = screenLeft +150
                displayScore.y = screenRight-100
                displayre = display.newText( "  The game is going restart", 0, 0, "Helvetica", 25 )
                displayre.x = screenLeft +150
                displayre.y = screenRight-200
                timer.performWithDelay(5000, function() storyboard.gotoScene("play", "fade", 1000); end)

                lostGame = true
            end
        end
    end
end

---

通过添加一个变量来检查您是否已经丢失，您可以防止它在您处于延迟状态时运行要离开的代码。

如Rob所愿添加一个计时器

timer.performWithDelay(5000, function() storyboard.gotoScene("play", "fade", 1000); end)

但你现在也有问题了。如果你已经吃了另一种食物，又吃了另一种呢？这将使多个计时器关闭，并可能出现故障，因为它将删除已删除的猴子

local lostGame = false

local function monkeyCollision( self, event )
    if event.phase == "began" then
        if event.target.type == "monkey" and event.other.type == "food" then

            print( "chomp!" )
            event.other.alpha = 0
            event.other:removeSelf() 
            addToScore(5)
            -- get points!
        else

            if lostGame == false then
                print("ow!")
                monkey.alpha = 0
                monkey:removeSelf()
                displayScore = display.newText( "The total score is " .. score , 0, 0, "Helvetica", 30 )
                displayScore.x = screenLeft +150
                displayScore.y = screenRight-100
                displayre = display.newText( "  The game is going restart", 0, 0, "Helvetica", 25 )
                displayre.x = screenLeft +150
                displayre.y = screenRight-200
                timer.performWithDelay(5000, function() storyboard.gotoScene("play", "fade", 1000); end)

                lostGame = true
            end
        end
    end
end

---

通过添加一个变量来检查您是否已经丢失，您可以防止它在您处于延迟状态时运行代码离开。

这是一个很好的观点！我只是让这件事发生在我身上，延迟了500毫秒。在我的例子中，不是用户选择了其他东西，而是它也会注册一个“双击”或触摸事件，导致下一个场景调用scene:show twick。这是一个很好的观点！我只是让这件事发生在我身上，延迟了500毫秒。在我的例子中，这并不是因为用户选择了其他东西，而是因为它也会注册一个“双击”或触摸事件，导致下一个场景调用scene:show两次。请注意这一点，原因由joehinkle11 befow提供！由于joehinkle11 befow提供的原因，请注意这一点！