Macos 如果一个单词不是'；列表中的t应用程序脚本

我正在写一个脚本，可以为我打开和关闭应用程序。基本上，我输入一个应用程序名，然后它打开应用程序。唯一的问题是，如果找不到应用程序，它会抛出一个错误并退出。我想让脚本只显示一个对话框，上面写着“找不到应用程序”

以下是我目前掌握的情况：

if userInput contains "Activate " then set {TID, text item delimiters} to {text item delimiters, {"Activate "}}
if length of userInput is less than or equal to 1 then say (resultString as string)
if length of userInput is greater than or equal to 2 then set resultString to text item 2 of userInput
set openApp to (resultString as string)
if userInput contains "Activate " then set text item delimiters to TID
if userInput contains "Activate " then tell application (openApp as string) to activate

顺便说一句，这只是我脚本的一个片段，这就是为什么这里有一些未定义的变量

我试过：

set appList to do shell script "cd /Applications; ls"
if openApp is not in appList then display dialog "App not found"

嗯，Applescript语法有时很烦人

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谢谢。

有一个

存在的应用程序

，但这也会弹出一个对话框，询问“xyz在哪里？”

因此，你能做的最好的事情似乎是：

tell application "Finder" to set appExists to (exists file myApp of folder "Applications" of startup disk)

if not appExists then
    display alert "App not found"
end if

您的代码是：

if userInput contains "Activate " then set {TID, text item delimiters} to {text item delimiters, {"Activate "}}
if length of userInput is less than or equal to 1 then say (resultString as string)
if length of userInput is greater than or equal to 2 then set resultString to text item 2 of userInput
set openApp to (resultString as string)

if userInput contains "Activate " then set text item delimiters to TID

tell application "Finder" to set appExists to (exists file (openApp & ".app") of folder "Applications" of startup disk)
if not appExists then
    display alert "App not found"
else
    if userInput contains "Activate " then tell application (openApp as string) to activate
end if

或者，如果用户按“取消”，则尝试捕获错误：

try
    if userInput contains "Activate " then tell application (openApp as string) to activate
on error
    display alert "App not found"
end try

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但是你没有看到一个弹出窗口，问“xyz在哪里？”我有，但是如果我按“取消”，我会收到一条奇怪的消息谢谢，最后的建议对我来说效果最好。