Matlab 在矩阵的每行仅生成一个非零元素

我想构造一个矩阵，其中我们不仅在每一行有一个“1”，而且在一个随机的位置也有一个“。e、 g

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我希望矩阵的大小为大小

m乘以n

。这项任务似乎很简单，但我不确定该怎么做。谢谢。

这将得到每列中要放入的1的数量，因为它只有1，我们被授权在转置后，新矩阵每行中只有一个1

参数是生成的矩阵中的行数和列数

function [M] = getMat(n,d)
    M = zeros(d,n);
    sz = size(M);
    nnzs = 1;
    inds = [];
    for i=1:n
        ind = randperm(d,nnzs);
        inds = [inds ind.'];
    end 
    points = (1:n);
    nnzInds = [];
    for i=1:nnzs
        nnzInd = sub2ind(sz, inds(i,:), points);
        nnzInds = [nnzInds ; nnzInd];
    end
    M(nnzInds) = 1; 
    M = M.';
end

例如：

getMat(5, 3)

ans =

     0     0     1
     1     0     0
     0     1     0
     1     0     0
     0     0     1

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我建议采取以下办法：

N = 3; M = 6; %defines input size
mat = zeros(M,N); %generates empty matrix of NxN
randCols = randi([1,N],[M,1]); %choose columns randomally
mat(sub2ind([M,N],[1:M]',randCols)) = 1; %update matrix

% generate a random integer matrix of size m by n
m = randi(5,[5 3]);

% find the indices with the maximum number in a row
[Y,I] = max(m, [], 2);

% create a zero matrix of size m by n
B = zeros(size(m));

% get the max indices per row and assign 1
B(sub2ind(size(m), 1:length(I), I')) = 1;

结果

mat =

 0     0     1
 1     0     0
 0     0     1
 0     0     1
 0     1     0
 0     1     0

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考虑这种方法：

N = 3; M = 6; %defines input size
mat = zeros(M,N); %generates empty matrix of NxN
randCols = randi([1,N],[M,1]); %choose columns randomally
mat(sub2ind([M,N],[1:M]',randCols)) = 1; %update matrix

% generate a random integer matrix of size m by n
m = randi(5,[5 3]);

% find the indices with the maximum number in a row
[Y,I] = max(m, [], 2);

% create a zero matrix of size m by n
B = zeros(size(m));

% get the max indices per row and assign 1
B(sub2ind(size(m), 1:length(I), I')) = 1;

结果：

B =

    0     1     0
    0     0     1
    1     0     0
    0     1     0
    1     0     0

参考：