利用MATLAB将函数的输出转换成另一个函数
不知道我做错了什么。我试图将函数疯狂升级的结果应用到我的新函数等级中,但我做错了什么利用MATLAB将函数的输出转换成另一个函数,matlab,function,nested,Matlab,Function,Nested,不知道我做错了什么。我试图将函数疯狂升级的结果应用到我的新函数等级中,但我做错了什么 function [newGrades]=GradeDist(grades) newGrades=crazyGrade(grades) % I want to take GradeDist(grades) %and use the parameter grades to pass through crazyGrade %and return it back to this function..
function [newGrades]=GradeDist(grades)
newGrades=crazyGrade(grades)
% I want to take GradeDist(grades)
%and use the parameter grades to pass through crazyGrade
%and return it back to this function...but I cant figure that out...
end
% I want to use the output of this function in GradeDist
function newGrades=crazyGrade(grades)
newGrades=upper(grades)
newGrades(grades=='A')='F';
newGrades(grades=='B')='D';
newGrades(grades=='C')='C';
newGrades(grades=='D')='B';
newGrades(grades=='F')='A';
newGrades(grades=='Y')='W';
end
当我在命令行中输入GradeDist('A')时。我没有得到任何输出。我想是因为我的文件名是crazyGrader函数的名称,当我更改它时,它似乎起作用了。如果有人感兴趣的话,我想这么做
function newwGrades=GradeDist(grade)
newwGrades=crazyGrader(grade)
end
function newGrades=crazyGrader(grades)
newGrades=upper(grades) % convert the string to uppercase letter
% so it will be a string.
newGrades(grades=='A')='F'; % index the grades and replace the grades
% according to the letter.
newGrades(grades=='B')='D';
newGrades(grades=='C')='C';
newGrades(grades=='D')='B';
newGrades(grades=='F')='A';
newGrades(grades=='Y')='W';
end
是字符串(数组)/单元格数组吗?请发布错误消息,否则很难推断出错误。这并不明显。还包括输入data@AndreasH. 当我在命令行中输入GradeDist('A')时。我没有得到任何输出。当我输入它时,我得到了一些东西(不幸的是,换行符没有正确显示):>>GradeDist('A')newGrades=A newGrades=F ans=FAlso请注意,由于newGrades(grades='A')='F',你永远不会得到“F”;新等级(等级='F')='A';;-)