Mongodb 根据$geoNear（目的地）进行筛选，并根据$geoNear（起点）进行排序

我想显示给定距离内的车手位置，并根据原点对其进行排序

这就是数据的样子

{ 
"_id" : ObjectId("5b5a9cd706f9b02068ebc4a6"), 
"name" : "Bangalore to hyderabad",
"locations" : [
    {
        "coordinates" : [
            77.5945627, 
            12.9715987
        ], 
        "_id" : ObjectId("5b5a9cd706f9b02068ebc4a8"), 
        "formattedAddress" : "Bengaluru, Karnataka, India", 
        "name" : "Bengaluru", 
        "type" : "Point", 
        "googlePlaceId" : "5b0d9fd719c9616d747b8a0d", 
        "placeType" : "origin" //***Sort by this***
    }, 
    {
        "coordinates" : [
            78.486671, 
            17.385044
        ], 
        "_id" : ObjectId("5b5a9cd706f9b02068ebc4a7"), 
        "formattedAddress" : "Hyderabad, Telangana, India", 
        "name" : "Hyderabad", 
        "type" : "Point", 
        "googlePlaceId" : "5b0d9fd719c9616d747b8a0d", 
        "locType" : "destination" // *****Filter by this***
    }
], 

}

这是我到目前为止做的家庭作业

return await Ride.aggregate([
    {
        $geoNear: {
            near: { type: "Point", coordinates: [ 77.5946,12.8716 ] },
            distanceField: "distance",
            maxDistance: 20000000, //200Kms
            query: { private: false },
            spherical: true
        }
    },
    // { "$sort": { "distance": 1 } },
    { "$skip": 0 },
    { "$limit": 30 }
]);

此查询基于所有位置点过滤数据，而不考虑位置类型

2dsphere是location.coordinates上的索引

{ 
"v" : NumberInt(2), 
"key" : {
    "locations.coordinates" : "2dsphere"
}, 
"name" : "locations.coordinates_2dsphere", 
"ns" : "projectName.documentName", 
"background" : true, 
"2dsphereIndexVersion" : NumberInt(3)

---

}我用另一种方法解决了这个问题

首先，我将“距离”字段添加到数据中。将原点和目标作为单独的对象而不是数组

{ 
"_id" : ObjectId("5b5a9cd706f9b02068ebc4a6"), 
"name" : "Bangalore to hyderabad",
"origin" : {
        "coordinates" : [
            77.5945627, 
            12.9715987
        ], 
        "_id" : ObjectId("5b5a9cd706f9b02068ebc4a8"), 
        "formattedAddress" : "Bengaluru, Karnataka, India", 
        "name" : "Bengaluru", 
        "type" : "Point", 
        "googlePlaceId" : "5b0d9fd719c9616d747b8a0d", 
    }, 
destination: {
        "coordinates" : [
            78.486671, 
            17.385044
        ], 
        "_id" : ObjectId("5b5a9cd706f9b02068ebc4a7"), 
        "formattedAddress" : "Hyderabad, Telangana, India", 
        "name" : "Hyderabad", 
        "type" : "Point", 
        "googlePlaceId" : "5b0d9fd719c9616d747b8a0d", 
    }

然后我在半径为1公里的原始场上查询发射geoNear，查询距离小于200公里

Ride.aggregate([
    {
        $geoNear: {
            near: { type: "Point", coordinates: [ 77.5946,12.8716 ] },
            distanceField: "distanceFromOrigin",
            maxDistance: 1000, //1Km
            query: { private: false, distance:{$lt:200}},
            spherical: true
        }
    },
    // { "$sort": { "distanceFromOrigin":1,"distance": 1 } },
    { "$skip": 0 },
    { "$limit": 30 }
]);

---

定义更好的方法这是解决这个问题的正确方法吗？在这个网站上，自以为是的问题是离题的。你需要用客观、可衡量的术语来定义“更好”或“正确”。没错，我重新定义并删除了固执己见的部分。我试图实现，排序的位置根据原点和目的地的半径过滤。类似于“向我显示从我附近开始并在我周围行驶200公里的列车列表”的答案，那么，您想显示距离某个点的限制范围内（例如200公里）的位置，按给定点的距离升序排列吗？