在symfony 2.1中使用mongodb进行用户身份验证

在Symfony 2.1的当前版本中，应该可以使用MongoDB作为SecurityBundle的用户提供程序，而无需使用FOSUserBundle（此处介绍：）

无法找出代码中的实际问题在哪里，但我无法使用预定义的用户登录

test:test

我的

security.yml

如下所示：

security: encoders: test\TestBundle\Document\User: plaintext providers: document_members: mongodb: { class: testTestBundle:User, property: username } firewalls: secured_area: pattern: ^/ http_basic: realm: "Login to TEST" access_control: - { path: ^/admin, roles: ROLE_ADMIN } role_hierarchy: ROLE_ADMIN: ROLE_USER Array ( [_id] => 4f59b5731c911ab41e001234 [username] => test [password] => test [roles] => Array ( [0] => ROLE_ADMIN ) [salt] => [isActive] => 1 )

test/TestBundle/Document/UserRepository.php

：

namespace test\TestBundle\Document; use Doctrine\ODM\MongoDB\DocumentRepository; use Symfony\Component\Security\Core\User\UserInterface; use Symfony\Component\Security\Core\User\UserProviderInterface; use Symfony\Component\Security\Core\Exception\UsernameNotFoundException; use Symfony\Component\Security\Core\Exception\UnsupportedUserException; class UserRepository extends DocumentRepository implements UserProviderInterface { public function loadUserByUsername($username) { $q = $this->createQueryBuilder() ->field('username')->equals((string) $username) ->getQuery(); try { $user = $q->getSingleResult(); } catch (NoResultException $e) { throw new UsernameNotFoundException(sprintf('Can\'t find Username "%s"', $username), null, 0, $e); } return $user; } public function refreshUser(UserInterface $user) { $class = get_class($user); if (!$this->supportsClass($class)) { throw new UnsupportedUserException(sprintf('Instances of "%s" are not supported.', $class)); } return $this->loadUserByUsername($user->getUsername()); } public function supportsClass($class) { return $class === 'test\TestBundle\Document\User'; } } （将导致现有控制器和视图）

预定义的

用户

-文档如下所示：

security: encoders: test\TestBundle\Document\User: plaintext providers: document_members: mongodb: { class: testTestBundle:User, property: username } firewalls: secured_area: pattern: ^/ http_basic: realm: "Login to TEST" access_control: - { path: ^/admin, roles: ROLE_ADMIN } role_hierarchy: ROLE_ADMIN: ROLE_USER Array ( [_id] => 4f59b5731c911ab41e001234 [username] => test [password] => test [roles] => Array ( [0] => ROLE_ADMIN ) [salt] => [isActive] => 1 ) 排列 ( [\u id]=>4f59b5731c911ab41e001234 [用户名]=>测试 [密码]=>测试 [角色]=>数组 ( [0]=>角色管理 ) [盐]=> [isActive]=>1 )

---

但是我不能在

/admin

上使用用户名

test

和密码

test

登录问题与在apache+fastCGI上使用symfony有关(https://github.com/symfony/symfony/pull/3551)

---

上述代码按预期工作。

答案已过时，已修复