Mongodb Mongo DB比较两个数组并添加缺少的元素
我有一个状态数组,如下所示Mongodb Mongo DB比较两个数组并添加缺少的元素,mongodb,mongodb-query,aggregation-framework,aggregate,Mongodb,Mongodb Query,Aggregation Framework,Aggregate,我有一个状态数组,如下所示 "statuses" : [ { "name" : "In Progress", "created_on" : ISODate("2020-04-20T19:00:07.681Z") }, { "name" : "Pending", "created_on" : ISODate("2020-04-20T19:00:07.886
"statuses" : [
{
"name" : "In Progress",
"created_on" : ISODate("2020-04-20T19:00:07.681Z")
},
{
"name" : "Pending",
"created_on" : ISODate("2020-04-20T19:00:07.886Z")
},
{
"name" : "Viewed",
"created_on" : ISODate("2020-04-20T20:10:04.733Z")
},
{
"name" : "Initial Viewed",
"created_on" : ISODate("2020-04-20T20:10:08.468Z")
},
{
"name" : "Opened",
"created_on" : ISODate("2020-04-21T01:37:08.582Z")
},
{
"name" : "Completed",
"created_on" : ISODate("2020-04-21T01:48:46.007Z")
}
]
我有另一个数组,其中:
"reference": ['In Progress', 'Pending', 'Sent', 'Initial Viewed', 'Viewed', 'Opened', 'Completed']
当我将我的第一个数组与引用数组进行比较时,可以看到,我想用当前ISODate()将第一个数组添加到第一个数组中的第一个数组中缺少“Sent”。我还希望我的第一个数组与第二个数组的顺序相同。通过运行reference
可以获得所需的顺序。以及将允许您查找单个匹配元素,并可在不匹配时用于构建新对象:
db.collection.aggregate([
{
$project: {
result: {
$map: {
input: "$reference",
as: "ref",
in: {
$let: {
vars: {
matched: {
$arrayElemAt: [ { $filter: { input: "$statuses", cond: { $eq: [ "$$ref", "$$this.name" ] } } }, 0 ]
}
},
in: {
$ifNull: [ "$$matched", { name: "$$ref", created_on: new Date() } ]
}
}
}
}
}
}
}
])