在MongoDB中查询内部ID

我有两套

1） 用户->带字段

name as String
emailId as String

 `userId as String.` (This will be the ID of the user and Foreign Key as per SQL)
 comment as String`

(二)

评级->带字段

name as String
emailId as String

 `userId as String.` (This will be the ID of the user and Foreign Key as per SQL)
 comment as String`

我为用户创建了一个记录，如下所示

{
    "_id": {
        "$oid": "565fe1294a27a93449751a9a"
    },
    "name": "Some name",
    "email": "somemail@gmail.com",
    "createdAt": {
        "$date": "2015-12-03T06:28:57.904Z"
    },
    "updatedAt": {
        "$date": "2015-12-03T06:28:57.904Z"
    }
}

{
    "_id": {
        "$oid": "565fefa30878764428d96be1"
    },
    "userId": "565fe1294a27a93449751a9a",
    "comment": "just a test comment",
    "createdAt": {
        "$date": "2015-12-03T07:30:43.409Z"
    },
    "updatedAt": {
        "$date": "2015-12-03T07:30:43.409Z"
    }
}

我已经创建了一个评级记录，看起来像

{
    "_id": {
        "$oid": "565fe1294a27a93449751a9a"
    },
    "name": "Some name",
    "email": "somemail@gmail.com",
    "createdAt": {
        "$date": "2015-12-03T06:28:57.904Z"
    },
    "updatedAt": {
        "$date": "2015-12-03T06:28:57.904Z"
    }
}

{
    "_id": {
        "$oid": "565fefa30878764428d96be1"
    },
    "userId": "565fe1294a27a93449751a9a",
    "comment": "just a test comment",
    "createdAt": {
        "$date": "2015-12-03T07:30:43.409Z"
    },
    "updatedAt": {
        "$date": "2015-12-03T07:30:43.409Z"
    }
}

现在我想做一个查询，返回用户完成的所有评分以及用户文档

如果我提出这样的问题

db.user.find({
   "userId" :"565fe1294a27a93449751a9a"
})

我得到的结果是

{
    "id": "565fefa30878764428d96be1",
    "userId": "565fe1294a27a93449751a9a",
    "comment": "just a test comment"
}

但我希望用户对象也包含在其中

{
    "id": "565fefa30878764428d96be1",
    "user": { "name": "Some name",
       "email": "somemail@gmail.com",
       "id": "565fe1294a27a93449751a9a"
    },
    "comment": "just a test comment"
}

或者甚至像这样的东西也会起作用

"rating": {
    "id": "565fefa30878764428d96be1",
    "userId": "565fe1294a27a93449751a9a",
    "comment": "just a test comment"
},
"user": {
    "id": "565fefa30878764428d96be1",
    "userId": "565fe1294a27a93449751a9a",
    "comment": "just a test comment"
}

---

在这里，您需要更改模式。您需要将用户类型从字符串更改为引用。如果您在评级中添加用户参考，那么这将很容易。若您添加了对用户模式的引用，那个么您可以在评级时填充用户。然后将获得带有评级的用户信息

参考示例：

User: {type: mongoose.Schema.ObjectId, ref: 'User'}

---

找到了我的精确解

从技术上讲，它在后端创建两个查询。通过响应时间发现了这一点

---

但无论如何，它解决了我的问题。

我使用了帆船和吃水线，根据本文档，我没有看到参考类型。你需要和mongodb合作。检查此链接：谢谢，但我在这里得到了确切的解决方案。