在Mono中导航后，XPathNavigator.SchemaInfo为空

我正在将C#与Mono一起使用，我想使用XPathNavigator浏览一个经过XML模式验证的XML文档。当我遍历文档时，我可以通过XPathNavigator.SchemaInfo属性获得每个元素的XML模式信息。但是，在调用XPathNavigator.MoveToFirstChild（）之后，XPathNavigator.SchemaInfo=null。这里有一个例子

using System;

using System.IO;
using System.Xml;
using System.Xml.XPath;
using System.Xml.Schema;

namespace XmlSchemaTest
{
    class Program
    {
        static void Main(string[] args)
        {
            XmlDocument xmlDocument = ReadAndValidateXmlFile(@"../test.xml", @"../test.xsd");

            if (xmlDocument == null)
                Console.WriteLine("Cannot open document or it didn't validate.");
            else
            {
                XPathNavigator xpathNavigator = xmlDocument.CreateNavigator();
                Console.WriteLine("XPathNavigator.SchemaInfo is " + ((xpathNavigator.SchemaInfo == null) ? "null" : "not null"));

                xpathNavigator.MoveToRoot();
                Console.WriteLine("Called XPathNavigator.MoveToRoot()");

                if(xpathNavigator.MoveToFirstChild())
                {
                    Console.WriteLine("XPathNavigator.LocalName after .MoveToFirstChild() succeeded = " + xpathNavigator.LocalName);
                    Console.WriteLine("XPathNavigator.NodeType value = " + xpathNavigator.NodeType.ToString());
                    Console.WriteLine("XPathNavigator.SchemaInfo is " + ((xpathNavigator.SchemaInfo == null) ? "null" : "not null"));
                }
            }

            //Console.ReadLine();
        }

        private static XmlDocument ReadAndValidateXmlFile(string xmlPath, string xsdPath)
        {
            // Load the XML Schema
            bool anyValidationErrors = false;
            XmlSchemaSet oSchemaSet = new XmlSchemaSet();
            ValidationEventHandler Handler = new ValidationEventHandler((object sender, ValidationEventArgs args) => {Console.WriteLine(args.Message); anyValidationErrors = true;} );
            oSchemaSet.ValidationEventHandler += Handler;
            XmlSchema oSchema = null;
            using (StreamReader sr = new StreamReader(xsdPath)) {
                oSchema = XmlSchema.Read(sr, Handler);  
            }
            if (anyValidationErrors || (oSchema == null)) {
                Console.WriteLine("Schema validation errors");
                return null;    
            }
            oSchemaSet.Add(oSchema);

            // Set up the Xml reader to do schema validation
            XmlReaderSettings xmlReaderSettings = new XmlReaderSettings();
            xmlReaderSettings.ValidationType = ValidationType.Schema;
            xmlReaderSettings.Schemas.Add(oSchemaSet);
            anyValidationErrors = false;
            xmlReaderSettings.ValidationEventHandler += new ValidationEventHandler((object sender, ValidationEventArgs args) => {Console.WriteLine(args.Message); anyValidationErrors = true;} );

            // Load the Xml and validate against schemer
            using (XmlReader xmlReader = XmlReader.Create(xmlPath, xmlReaderSettings))
            {
                XmlDocument xmlDocument = new XmlDocument();
                xmlDocument.Load(xmlReader);

                if (anyValidationErrors) {
                    Console.WriteLine("Xml validation errors");
                    return null;
                }
                else
                    return xmlDocument;
            }
        }
    }
}

使用这个XSD

<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="TEST" 
            targetNamespace="urn:test" 
            xmlns:tst="urn:test" 
            xmlns="urn:test" 
            elementFormDefault="qualified"
            xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="TestElement">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="SubEle">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="ChildEle" type="xs:unsignedInt" />
            </xs:sequence>
          </xs:complexType>
        </xs:element>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>

有人对发生了什么或我做错了什么有意见吗

谢谢 戴夫

PS我说“在mono中”，因为这是我正在使用的，我还不能在Windows上确认。此外，它的运行时版本是.NET4.0，发生在调试和发布中

更新我刚刚在Windows上尝试了这个，得到了这个结果

XPathNavigator.SchemaInfo is not null
Called XPathNavigator.MoveToRoot()
XPathNavigator.LocalName after .MoveToFirstChild() succeeded = TestElement
XPathNavigator.NodeType value = Element
XPathNavigator.SchemaInfo is not null
Press any key to continue . . .

---

那么也许是一个单一的东西？

我最后提交了一个bug-

---

我通过从XmlSchemaSet中的根XmlSchemaElement进行遍历并通过XmlQualifiedName记录所有XmlSchemaElement和XmlSchemaAttribute来解决这个问题，然后在XPathNavigator遍历XmlDocument时，使用XPathNavigator中的XmlQualifiedName来查找XmlSchemaElement/XmlSchemaAttribute。它有点可行，但也不可行，因为XmlQualifiedName不足以唯一标识模式中的元素，例如元素可以在模式中的不同位置使用不同的maxOccurs/minOccurs值。

Mono JIT编译器版本2.10.5（Debian 2.10.5-1ubuntu0.1）版权（C）2002-2011 Novell，Inc，Xamarin，公司和贡献者。www.mono-project.com TLS:u thread SIGSEGV:altstack通知：epoll体系结构：amd64已禁用：无其他：softdebug LLVM:受支持，未启用。GC：在Ubuntu11.10上包括Boehm（带有类型化GC和并行标记），如果它在Windows上工作（使用MS.NET，而不是Mono），但在Mono上不工作，那么：首先，将Mono更新到3.x，再次测试，如果它仍然不工作，那么在这里提交一个bug中的最小测试用例：

XPathNavigator.SchemaInfo is not null
Called XPathNavigator.MoveToRoot()
XPathNavigator.LocalName after .MoveToFirstChild() succeeded = TestElement
XPathNavigator.NodeType value = Element
XPathNavigator.SchemaInfo is null

XPathNavigator.SchemaInfo is not null
Called XPathNavigator.MoveToRoot()
XPathNavigator.LocalName after .MoveToFirstChild() succeeded = TestElement
XPathNavigator.NodeType value = Element
XPathNavigator.SchemaInfo is not null
Press any key to continue . . .