如何将自定义分号分隔的属性列表添加到msbuild taks属性
下面是一个简单的测试项目如何将自定义分号分隔的属性列表添加到msbuild taks属性,msbuild,Msbuild,下面是一个简单的测试项目 <?xml version="1.0" encoding="utf-8"?> <Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0" DefaultTargets="configure"> <!-- - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" ToolsVersion="4.0" DefaultTargets="configure">
<!-- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -->
<PropertyGroup>
<param>var1=val1,var2=val2</param>
</PropertyGroup>
<!-- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -->
<Target Name="configure" DependsOnTargets="" Outputs="">
<MSBuild
Projects="$(MSBuildProjectFullPath)"
Properties="component=c1;$(param.Replace(',',';'))"
Targets="process"/>
</Target>
<!-- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -->
<Target Name="process">
<Message Text="[$(component)][$(var1)][$(var2)]"/>
</Target>
</Project>
var1=val1,var2=val2
我希望看到
[c1][val1][val2]
但不幸的是,msbuild没有解析字符串和输出中的其他属性
[c1][val1;var2=val2][]
如何帮助msbuild?
谢谢
解决方案:使用[MSBuild]::Unescape
<PropertyGroup>
<p>var1=val1,var2=val2</p>
<param>$([MSBuild]::Unescape($(p.Replace(',',';'))))</param>
</PropertyGroup>
var1=val1,var2=val2
$([MSBuild]::Unescape($(p.Replace(',',';'))
您应该使用项组对参数和值的集合进行逻辑分组,并使用MSBUILD转换来获取希望看到的输出
<Target Name="SemiColon">
<ItemGroup>
<Parm Include="Parm1">
<Value>Val1</Value>
</Parm>
<Parm Include="Parm2">
<Value>Val2</Value>
</Parm>
<Parm Include="Parm3">
<Value>Val3</Value>
</Parm>
<Parm Include="Parm4">
<Value>Val4</Value>
</Parm>
<ParamLine Include="%(Parm.identity )=%(Parm.Value)" />
</ItemGroup>
<Message Importance="High"
Text="Parameter Name and Value: @(ParamLine, ';')" />
<Message Importance="High"
Text="Just values: @(Parm -> MetaData('Value'))" />
</Target>
谢谢我的错误。我没有描述为什么要使用逗号分隔的名称-值对列表。在上面的示例中,我作为msbuild参数接收,无法使用ItemGroup构造它。例如,我将上面的项目文件称为:
Parameter Name and Value: Parm1=Val1;Parm2=Val2;Parm3=Val3;Parm4=Val4
Just values: Val1;Val2;Val3;Val4