Mule 组合数组元素并重新格式化输出

我有一个输入JSON，我想使用Mule的Dataweave2.0转换它

下面是输入JSON

[
   {
     "data1": {
                "role": "analyst",
                "name": "ABC"
     },
     "data2": {
                "role": "analyst",
                "name": "DEF"
     }
  },
  {
     "data1": {
                "role": "RM",
                "name": "PQRS"
     },
     "data2": {
                "role": "analyst",
                "name": "QWE"
     }
  }
]

我们希望输出如下：

[
  {
     "role": "analyst",
     "name": "ABC"
  },
  {
     "role": "analyst",
     "name": "DEF"
  },
  {
     "role": "RM",
     "name": "PQRS"
  },
  {
     "role": "analyst",
     "name": "QWE"
  }
]

---

我尝试了不同的选择使用地图，拔毛和展平，但无法得到解决方案。请帮助我使用此转换函数。

如果响应对象的顺序很重要：

%dw 2.0
output application/json
---
flatten (payload map (flatten $))

%dw 2.0
output application/json
---
payload.data1 ++ payload.data2

如果订单不重要：

%dw 2.0
output application/json
---
flatten (payload map (flatten $))

%dw 2.0
output application/json
---
payload.data1 ++ payload.data2

---

如果响应对象的顺序很重要：

%dw 2.0
output application/json
---
flatten (payload map (flatten $))

%dw 2.0
output application/json
---
payload.data1 ++ payload.data2

如果订单不重要：

%dw 2.0
output application/json
---
flatten (payload map (flatten $))

%dw 2.0
output application/json
---
payload.data1 ++ payload.data2

---

如果您想维持订单，您可以：

1） 使用

reduce

遍历元素，对于数组中的每个对象，累加

data1

和

data2

%dw 2.0
output application/json
---
payload reduce (item, acc = []) -> (acc << item.data1 << item.data2)

---

如果您想维持订单，您可以：

1） 使用

reduce

遍历元素，对于数组中的每个对象，累加

data1

和

data2

%dw 2.0
output application/json
---
payload reduce (item, acc = []) -> (acc << item.data1 << item.data2)