Mysql 数据库设计：使用多个选择存储多个选项的最佳方式

因此，我试图确定实现这一点的最佳方式： 我会尽可能地简单，但要提供足够的信息

我有一个大数据集的数据库。在本例中，每辆车都是 有人在找你

我有一张桌子：

CREATE TABLE cars (
`car_id` INT(10),
`car_name` VARCHAR(20)
)  

和选项表一样

CREATE TABLE `car_selected_options` (
`car_sel_id`   INT       NOT NULL AUTO_INCREMENT,
`car_id`       INT       //the id of the car record created
`value`        INT       //id of info in a ref table
`key`          VARCHAR(20)   //from the car_option_reference,
)

例如：该值是ref表中更多信息的id（注2）

我需要找到所有红色的汽车id，并且有导航和收音机我正在做类似的事情：

SELECT distinct(c.car_id)
FROM `car` c 
   INNER JOIN `car_selected_options` AS o ON c.car_id = o.car_id
WHERE 
o.car_sel_id IN 
        ( SELECT car_sel_id 
            FROM car_selected_options so 
            WHERE so.`key` = 'exterior_color' 
              AND so.value IN ('10' ) AND b.buyer_id = bm.buyer_id )
    AND
o.car_sel_id IN 
        ( SELECT car_sel_id 
            FROM car_selected_options so 
            WHERE so.`key` = 'electronics'  
              AND so.value IN ('100','101' ) AND b.buyer_id = bm.buyer_id )

car_exterior_color (could have one entry per car or multiples if this person is ok with a red or a blue colored car)
car_interior_color 
car_electronics

或者，与其将键和所有内容放在一个表中，不如将每个键都放在一个选项中，每个选项都有单独的表，例如：

SELECT distinct(c.car_id)
FROM `car` c 
   INNER JOIN `car_selected_options` AS o ON c.car_id = o.car_id
WHERE 
o.car_sel_id IN 
        ( SELECT car_sel_id 
            FROM car_selected_options so 
            WHERE so.`key` = 'exterior_color' 
              AND so.value IN ('10' ) AND b.buyer_id = bm.buyer_id )
    AND
o.car_sel_id IN 
        ( SELECT car_sel_id 
            FROM car_selected_options so 
            WHERE so.`key` = 'electronics'  
              AND so.value IN ('100','101' ) AND b.buyer_id = bm.buyer_id )

car_exterior_color (could have one entry per car or multiples if this person is ok with a red or a blue colored car)
car_interior_color 
car_electronics

而不是执行这些多个子选择（可能是多个子选择），而是执行多个内部联接

我希望这是有道理的

---

感谢您的帮助，您发布的查询中似乎缺少了一些内容，因为我看不到“b”和“bm”表是什么。忽略该子句，您可以大大简化查询，而无需执行多个子选择：

SELECT c.car_id
FROM `car` c 
   INNER JOIN `car_selected_options` AS o ON c.car_id = o.car_id
WHERE 
   (o.key = 'exterior_color' AND o.value = 10) OR
   (o.key = 'electronics' AND o.value = 100) OR
   (o.key = 'electronics' AND o.value = 101) OR
GROUP BY c.car_id
HAVING COUNT(*) = 3;

本例中的“3”是您应用的标准数量。这里的诀窍是，对于每个匹配的汽车，您应该正好有三个匹配的行，因此，如果您按汽车id分组，并按计数（*）过滤=3，您将只选择符合所有条件的汽车