Mysql 为每位医生制作一份预约清单;包括医生姓名、患者姓名、日期、时间和持续时间
我有三张桌子Mysql 为每位医生制作一份预约清单;包括医生姓名、患者姓名、日期、时间和持续时间,mysql,database,Mysql,Database,我有三张桌子 医生 人 任命 表格结构为: 医生表: +-----------+----------+---------+----------------+----------------+ | doctor_id | phone_no | room_no | date_qualified | date_appointed | +-----------+----------+---------+----------------+----------------+ | 50 |
- 医生
- 人
- 任命
+-----------+----------+---------+----------------+----------------+
| doctor_id | phone_no | room_no | date_qualified | date_appointed |
+-----------+----------+---------+----------------+----------------+
| 50 | 1234 | 1 | 1963-09-01 | 1991-05-10 |
| 51 | 1235 | 2 | 1973-09-12 | 1991-05-10 |
| 52 | 1236 | 3 | 1990-10-02 | 1993-04-01 |
| 53 | 1237 | 4 | 1965-06-30 | 1994-03-01 |
+-----------+----------+---------+----------------+----------------+
人员表
+-----------+----------+-----------+---------------+------+
| person_id | initials | last_name | date_of_birth | sex |
+-----------+----------+-----------+---------------+------+
| 100 | T | Williams | 1972-01-12 | m |
| 101 | J | Garcia | 1981-03-18 | f |
| 102 | W | Fisher | 1950-10-22 | m |
| 103 | K | Waldon | 1942-06-01 | m |
| 104 | P | Timms | 1928-06-03 | m |
| 105 | A | Dryden | 1944-06-23 | m |
| 106 | F | Fogg | 1955-10-16 | f |
| 150 | T | Saj | 1994-06-17 | m |
| 50 | A | Cameron | 1937-04-04 | m |
| 51 | B | Finlay | 1948-12-01 | m |
| 52 | C | King | 1965-06-06 | f |
| 53 | D | Waldon | 1938-07-08 | f |
+-----------+----------+-----------+---------------+------+
预约表
+-----------+------------+------------+-----------+---------------+
| doctor_id | patient_id | appt_date | appt_time | appt_duration |
+-----------+------------+------------+-----------+---------------+
| 50 | 100 | 1994-08-10 | 10:00:00 | 10 |
| 50 | 100 | 1994-08-16 | 10:50:00 | 10 |
| 50 | 102 | 1994-08-21 | 11:20:00 | 20 |
| 50 | 103 | 1994-08-10 | 10:10:00 | 10 |
| 50 | 104 | 1994-08-10 | 10:20:00 | 20 |
| 52 | 102 | 1994-08-10 | 10:00:00 | 10 |
| 52 | 105 | 1994-08-10 | 10:10:00 | 10 |
| 52 | 150 | 2014-03-10 | 12:00:00 | 15 |
| 53 | 106 | 1994-08-10 | 11:30:00 | 10 |
+-----------+------------+------------+-----------+---------------+
我需要创建一个查询来生成每个医生的预约列表,包括医生姓名、患者姓名以及预约的日期、时间和持续时间。结果应按医生姓名和预约日期/时间排序
我尝试了以下代码:
select person.last_name, person.initials, person.last_name, appointment.appt_date, appointment.appt_time, appointment.appt_duration -> from doctor inner join appointment on doctor.doctor_id = appointment.doctor_id -> inner join person on person.person_id = appointment.patient_id -> order by person.initials, person.last_name, appointment.appt_date, appointment.appt_time;
我得到了下面的结果,没有医生的名字,而且姓氏有两列,而应该只有一列
+-----------+----------+-----------+------------+-----------+---------------+
| last_name | initials | last_name | appt_date | appt_time | appt_duration |
+-----------+----------+-----------+------------+-----------+---------------+
| Dryden | A | Dryden | 1994-08-10 | 10:10:00 | 10 |
| Fogg | F | Fogg | 1994-08-10 | 11:30:00 | 10 |
| Waldon | K | Waldon | 1994-08-10 | 10:10:00 | 10 |
| Timms | P | Timms | 1994-08-10 | 10:20:00 | 20 |
| Saj | T | Saj | 2014-03-10 | 12:00:00 | 15 |
| Williams | T | Williams | 1994-08-10 | 10:00:00 | 10 |
| Williams | T | Williams | 1994-08-16 | 10:50:00 | 10 |
| Fisher | W | Fisher | 1994-08-10 | 10:00:00 | 10 |
| Fisher | W | Fisher | 1994-08-21 | 11:20:00 | 20 |
+-----------+----------+-----------+------------+-----------+---------------+
姓氏提交2次,因为您选择了它2次
select person.last_name, <------ here
person.initials, person.last_name, <---- here
appointment.appt_date,
appointment.appt_time,
appointment.appt_duration
from doctor
inner join appointment on doctor.doctor_id = appointment.doctor_id
inner join person on person.person_id = appointment.patient_id
order by
person.initials,
person.last_name,
appointment.appt_date,
appointment.appt_time;
不,医生表上没有医生的名字,医生的名字和病人的名字在persons表中。在当前的情况下,可以检索医生的名字,但是我需要将这些带有数据的表发布到sqlfiddle.com上,我们可以进行查询。我的意思是你在sqlfiddle.com中添加表和数据,这样我们就可以看到!!我已经将表格和数据添加到sqlfiddle.com,现在该怎么做欢迎用户3472448。请注意你的问题的表达方式,这样人们可以更容易地理解你的问题,并可能帮助你。在询问模式下,您可以使用帮助部分。(快速或详细)。欢迎再次光临。这个问题很好。你的错误在别处。:-)正如你所看到的,我也没能做到。最好的比“更好”更好。幸亏cpburnz@Strawberry亲爱的朋友,问题最初的显示方式真的很难理解。我试着编辑。我觉得更好。正如你所看到的,cpburnz让它变得更好了。所以请不要对彼此无礼。正如你们所看到的,问题的主人是新来的,所以,我也不是一个专家,但我尽了我最大的努力,就像user3472448@AndreChenier你显然很困惑。
select person.last_name,
person.initials,
d.last_name as DoctorName,
appointment.appt_date,
appointment.appt_time,
appointment.appt_duration
from appointment
inner join doctor on doctor.doctor_id = appointment.doctor_id
left join person on person.person_id = appointment.patient_id
left join
(
select * from person
)d
on d.person_id = appointment.doctor_id
order by
person.initials,
person.last_name,
appointment.appt_date,
appointment.appt_time;